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Kisachek [45]
3 years ago
12

a line represented by y = 5x − 2 and a line perpendicular to it intersect at r(1, 3). what is the equation of the perpendicular

line
Mathematics
1 answer:
Snezhnost [94]3 years ago
5 0
Y=ax+b, y=cx+d (a≠0, c≠0)
If the two line cross perpendicularly ⇔ ac= -1

So a tangent of the perpendicular line is "-(1/5)".

Then, the equation of the perpendicular line is y=-(1/5)x+a (a is <span> y-intercept</span>).

On the other hand, this equation pass r(1, 3), so 

3 = -(1/5) times 1 + a

∴ a=16 / 5 

Therefore, y=-(1/5)x+16 /5 is answer.

By the way, I'm Japanese so if you find some mistakes in my English, please let me know.


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Step-by-step explanation:

4 0
2 years ago
Line g is shown on the graph.
bogdanovich [222]

The equation of the line g that passes through points (-3, 2) and (0, 5), in slope-intercept form, is: y = x + 5.

<h3>How to Write the Equation of a Line in Slope-intercept Form?</h3>

Given the coordinates of two points that lie on a straight line on a graph, the equation that represents the line in slope-intercept form can be expressed as, y = mx + b, where:

Slope = m = change in y / change in x

y-intercept = b (the value of y when x = 0).

The coordinates of the two points on line g is given as:

(-3, 2) = (x1, y1)

(0, 5) = (x2, y2).

Find the slope (m) of the line:

Slope (m) = (5 - 2)/(0 - (-3))

Slope (m) = 3/3

Slope (m) = 1.

Y-intercept (b) = 5

Substitute m = 1 and = 5 into y = mx + b:

y = x + 5

The equation of the line in slope-intercept form is: y = x + 5.

Learn more about the slope-intercept equation on:

brainly.com/question/1884491

#SPJ1

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