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andrezito [222]
3 years ago
15

Is (6,7) a solution to the inequality 15x+11y>12

Mathematics
2 answers:
astra-53 [7]3 years ago
8 0

Answer:

(6,7) is a solution

Step-by-step explanation:

To determine if (6,7) is a solution, we substitute the point in and see if the inequality is true

15x+11y>12

15(6) + 11(7) >12

90+77 > 12

167>12

This is true so (6,7) is a solution

Aleksandr [31]3 years ago
6 0

The point (6,7) means that x = 6 and y = 7 pair up together. Let's plug them into the inequality.

15*x + 11*y > 12

15*6 + 11*7 > 12 ... replace x with 6, y with 7

90 + 77 > 12

167 > 12 ... this inequality is true since 167 is larger than 12

Because the last inequality is true, this means the first inequality is true when (x,y) = (6,7).

Therefore, (6,7) is a solution to the inequality.

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What is the greatest common factor of 72x^2y and 18xy?
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The GCF is the number or variables you can get out of a a term or multiple terms, when you get it out you have to be able to multiply it again and get the same terms as before for example the GCF of here is 18xy because both numbers can be divided in 18 and they both share 1 x and 1 y in common... Now divide to get your answer put the GCF outside the parenthesis and the numbers divided inside

18xy(4x + 1) if you do distributive property and multiply it you will get 72x2y+18xy see they match so the GCF of "18xy" is correct....

Hope this helped
5 0
3 years ago
Read 2 more answers
Factories 54m3n + 81m4n2 b) 15x2y3z + 25x3y2z + 35x2y2z​
Oliga [24]

<u>Part a)</u>

Given the expression

54m^3n\:+\:81m^4n^2

Apply exponent rule:    a^{b+c}=a^ba^c

54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn     ∵ m^4n^2=m^3mnn

Rewrite 81 as 3 · 27

Rewrite 54 as 2 · 27

                             =2\cdot \:27m^3n+3\cdot \:27m^3mnn

Factor out the common term:   27m³n

                              =27m^3n\left(2+3mn\right)      

Therefore,

54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn=27m^3n\left(2+3mn\right)

<u>Part B)</u>

Given the expression

15x^2y^3z+25x^3y^2z+35x^2y^2z

Apply exponent rule:    a^{b+c}=a^ba^c

15x^2y^3z+25x^3y^2z+35x^2y^2z=15x^2y^2yz+25x^2xy^2z+35x^2y^2z

Rewrite as

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Factor out common term 5y²x²z

                                                =5y^2x^2z\left(3y+5x+7\right)

Therefore,

15x^2y^3z+25x^3y^2z+35x^2y^2z=5y^2x^2z\left(3y+5x+7\right)

8 0
3 years ago
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Answer:

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The diagram shows a square.
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Answer:

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Assuming it grows 3% each year it would be <span>385,700</span>
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