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Katyanochek1 [597]
3 years ago
10

48 divided by 2 times 0.9+0.3

Mathematics
2 answers:
Lynna [10]3 years ago
5 0
48 ÷ 2 = 24
0.9 + 0.3 = 1.2
24 x 1.2 = 28.8

hope this helps.
Feliz [49]3 years ago
4 0
The answer will be 2.88 hope this helps
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Salt flows into the tank at a rate of

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and flows out at a rate of

(Q(t)/60 lb/gal) * (6 gal/min) = 6Q(t) lb/min

The net rate of change of the amount of salt in the tank at time t is then governed by

\dfrac{\mathrm dQ}{\mathrm dt}=3-6Q

Solve for Q:

\dfrac{\mathrm dQ}{\mathrm dt}+6Q=3

e^{6t}\dfrac{\mathrm dQ}{\mathrm dt}+6e^{6t}Q=3e^{6t}

\dfrac{\mathrm d}{\mathrm dt}[e^{6t}Q]=3e^{6t}

e^{6t}Q=\dfrac{e^{6t}}2+C

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10=\dfrac12+C\implies C=\dfrac{19}2

so that the amount of salt in the tank at time t is given by

\boxed{Q(t)=\dfrac{1+19e^{-6t}}2}

4 0
3 years ago
Find the value of <br> x<br> y, and <br> z in the parallelogram below.
EastWind [94]
Let A be the angle of 79 degrees
B be the angle of (5y-4) degrees
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We get, angle A = angle C
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We get, x+5=79
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Angle B = Angle D
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Since there’s two variables here, we can’t use the property of “opposite angles are equivalent”
We have to use another property which is adjacent angles are equal
Therefore, we can find angle D
Angle D + Angle A=180
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6 0
1 year ago
Make q the subject of the formula
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Answer:

q = 2p - 1/3

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Lapatulllka [165]

Answer:

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Answer:

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Step-by-step explanation:

Given

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Green Ribbon = ⅛

¾ ÷ ⅛

= ¾ * 8

= 24/8

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This is an exact multiple of ¾. So, the green ribbon will be collected.

Testing the last ribbon

Blue = ¼

¾ ÷ ¼

= ¾ * 4

= 3

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Hence, the green and blue ribbons will be collected at ¾ mile mark

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3 years ago
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