Salt flows into the tank at a rate of
(1/2 lb/gal) * (6 gal/min) = 3 lb/min
and flows out at a rate of
(Q(t)/60 lb/gal) * (6 gal/min) = 6Q(t) lb/min
The net rate of change of the amount of salt in the tank at time
is then governed by

Solve for
:


![\dfrac{\mathrm d}{\mathrm dt}[e^{6t}Q]=3e^{6t}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Be%5E%7B6t%7DQ%5D%3D3e%5E%7B6t%7D)


The tank starts with 10 lb of salt, so that Q(0) = 10. This gives us

so that the amount of salt in the tank at time
is given by

Let A be the angle of 79 degrees
B be the angle of (5y-4) degrees
C be the angle of (x+5) degrees
D be the angle of (9z-7) degrees
According to the property of parallelogram
Opposite angles are equal
We get, angle A = angle C
Since angle A = 79 degrees
And angle C = (x+5) degrees
We get, x+5=79
=> x=79-5=74.
Angle B = Angle D
(5y-4)=(9z-7)
Since there’s two variables here, we can’t use the property of “opposite angles are equivalent”
We have to use another property which is adjacent angles are equal
Therefore, we can find angle D
Angle D + Angle A=180
=> 9z-7 =180-79
z=108/9
z=12
Since (5y-4)=(9z-7)
Substitute z=12 in
We get, 5y-4=101
y= 105/5
y= 21
Therefore, x=74, y=21 and z=12.
Answer:
q = 2p - 1/3
Step-by-step explanation:
2q + 2p = 1+5q
2q = 1+5q-2p
-3q=1-2p
-q = 1-2p/3
q= 2p-1/3
Answer:
11/9
Step-by-step explanation:
It's called a calculator
Pls give Brainliest!!
Answer:
Green and Blue ribbon
Step-by-step explanation:
Given
They collect
Red Ribbon = ½ mile
Green Ribbon = ⅛ mile
Blue Ribbon = ¼ mile
To find?
Which colors of ribbons will be collected at the ¾ mile mark.
The interpretation of the question is to test which of the above fractions can divide ¾ without a remainder; in other words, multiples of ¾.
Testing each fraction.
Red Ribbon = ½
¾ ÷ ½
= ¾ * 2
= 3/2
= 1.5 or 1 Remainder 1
This is not an exact multiple of ¾. So, the red ribbon won't be passed here.
Green Ribbon = ⅛
¾ ÷ ⅛
= ¾ * 8
= 24/8
= 3
This is an exact multiple of ¾. So, the green ribbon will be collected.
Testing the last ribbon
Blue = ¼
¾ ÷ ¼
= ¾ * 4
= 3
This is an exact multiple of ¾. So, the blue ribbon will be collected.
Hence, the green and blue ribbons will be collected at ¾ mile mark