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Brilliant_brown [7]
3 years ago
14

Use the lim f(x)-f(a)/x-a to find the derivative.

Mathematics
1 answer:
Tresset [83]3 years ago
4 0
Hello,

f(x)-f(a)= -3x²-5x+1-(-3a²-5a+1)=-3(x²-a²)-5(x-a)=-3(x-a)(x+a)-5(x-a)
=-(x-a)(3(x+a)+5)
=-(x-a)(3x+3a+5)

lim (f(x)-f(a))/(x-a)=- lim (3x+3a+5)=3a+3a+5=-6a-5
if a=1==>-6*1-5=-11

Otherwise
f'(x)=-6x-5
f'(1)=-6-5=-11



at point(1,-7)

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goldenfox [79]

so a quadrilateral is a figure with 4 sides. So looking at the picture I see 5 rhombi and 7 squares. So all together thats 12 quadrilaterals  

So to find the ration you have to do:

amount of thing: whole

so in this case it would be

12:24

which you can simplify

normally you'd simplify to 1:2 but that doesn't seem like an option so I'd go with the one closest to that ratio


4 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=5%20%5Csqrt%7B15%7D%20" id="TexFormula1" title="5 \sqrt{15} " alt="5 \sqrt{15} " align="absmid
PSYCHO15rus [73]
The answer is 1.71......
5 0
3 years ago
A cookie recipe that yields 24 cookies requires 1 3/4 cups of butter. When the ingredients in this recipe are increased proporti
erik [133]

Answer:

5 1/4

Step-by-step explanation:

* is multiplication

1 3/4 is 1.75

so

24/1.75 = 72/×

1.75 * 72 = 24 * x

126 = 24x

24x = 126

x = 5.25 or 5 1/4

8 0
3 years ago
if the breadth of rectangle in one third of its length and perimeter is 80 cm find length and breadth of rectangle​
LiRa [457]

Answer:

length = 30 cm

Breadth = 10 cm

Step-by-step explanation:

Length = x cm

Breadth = (1/3)x

Perimeter = 80 cm

2(length + breadth) = 80

2* (x + (1/3)x) = 80

2*(\frac{3}{3}x+\frac{1}{3}x) = 80\\\\2*(\frac{4}{3}x) = 80\\\\\frac{8}{3}x = 80\\\\x = 80*\frac{3}{8}\\\\x = 10*3

x = 30cm

length = 30 cm

breadth = \frac{1}{3}*30=10 cm

6 0
3 years ago
Find the coordinates of the endpoint of the image?
ra1l [238]

Given:

The graph of a line segment.

The line segment AB translated by the following rule:

(x,y)\to (x+4,y-3)

To find:

The coordinates of the end points of the line segment A'B'.

Solution:

From the given figure, it is clear that the end points of the line segment AB are A(-2,-3) and B(4,-1).

We have,

(x,y)\to (x+4,y-3)

Using this rule, we get

A(-2,-3)\to A'(-2+4,-3-3)

A(-2,-3)\to A'(2,-6)

Similarly,

B(4,-1)\to B'(4+4,-1-3)

B(4,-1)\to B'(8,-4)

Therefore, the endpoint of the line segment A'B' are A'(2,-6) and B'(8,-4).

5 0
3 years ago
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