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olya-2409 [2.1K]
3 years ago
7

Please help!!

Mathematics
2 answers:
sveta [45]3 years ago
6 0
For this case we have the following equation:
 d =  \sqrt{\frac{3h}{2}}
 Where,
 d: the distance they can see in thousands
 h: their eye-level height in feet
 For Kaylib:
 d = \sqrt{\frac{3(48)}{2}}
 d=\sqrt{3(24)}
 d=\sqrt{72}
 d=6\sqrt{2}
 For Addison:
 d = \sqrt{\frac{3(85\frac{1}{3})}{2}}
 d = \sqrt{\frac{256}{2}}
 d=\sqrt{128}
 d=8\sqrt{2}
 Subtracting both distances we have:
 8\sqrt{2} - 6\sqrt{2} = 2\sqrt{2}
 Answer:
 
2\sqrt{2}
 B. 2√2 mi
hammer [34]3 years ago
6 0

Answer:

B. 2 sqrt 2 is the answer!!

Step-by-step explanation:

just took the test of edge2020

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Prime factor tree of 385
timama [110]


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Read 2 more answers
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