Question

Please help!!

Answer 1

For this case we have the following equation:
 $d = \sqrt{\frac{3h}{2}}$
 Where,
 d: the distance they can see in thousands
 h: their eye-level height in feet
 For Kaylib:
 $d = \sqrt{\frac{3(48)}{2}}$
 $d=\sqrt{3(24)}$
 $d=\sqrt{72}$
 $d=6\sqrt{2}$
 For Addison:
 $d = \sqrt{\frac{3(85\frac{1}{3})}{2}}$
 $d = \sqrt{\frac{256}{2}}$
 $d=\sqrt{128}$
 $d=8\sqrt{2}$
 Subtracting both distances we have:
 $8\sqrt{2} - 6\sqrt{2} = 2\sqrt{2}$
 Answer:
 $2\sqrt{2}$
 B. 2√2 mi

Answer 2

Answer:

B. 2 sqrt 2 is the answer!!

Step-by-step explanation:

just took the test of edge2020