At birth, one puppy weighs 15/16 pounds. A second puppy weighs 1 and 1/8 pounds. How much more did the second puppy weigh?
1 answer:
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Answer:
- (a) C(d) = 270 + 0.20d
- (b) C(1800) = 630
- (c) see attached (lower right graph). The slope represents the cost (in dollars) per mile.
- (d) It represents the fixed cost (amount she pays even if she does not drive)
- (e) the cost increases as the number of miles driven increases
Step-by-step explanation:
(a) You are given two points, (d, C) = (360, 342) and (780, 426). The two-point form of the equation for a line can be helpful.
... y = (y2 -y1)/(x2 -x1)(x -x1) +y1
Using the given points and variables, ...
... C = (426 -342)/(780 -360)(d -360) +342
... C = (84/420)(d -360) +342
... C = 0.20d +270 . . . . the equation for cost as a function of miles driven
(b) Fill in the value for d and do the arithmetic.
... C = 0.20·1800 +270 = 360 +270 = 630
(c) The slope of the curve is (change in dollars)/(change in miles) = $/mile, the cost of each mile driven. (It is $0.20 per mile.)
(d) The C-intercept is C(0) = cost for 0 miles driven. (It is $270.)
(e) Both your own experience and the problem statement tell you that the cost of vehicle operation varies with miles driven. If nothing else, you need to pay more for gas the farther you drive.
(In real life, you don't expect the model to be exactly linear, becasue you get a large jump in cost when you reach certain maintenance interval miles: 15,000, 30,000, and so on.)
