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astra-53 [7]
3 years ago
5

Will crown brainliest

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
8 0

Answer: B)

Step-by-step explanation:

If y = z then replace z for y in the second equation.

2 y + z = 12

2y + y = 12

3y = 12

y = 4

This also means z = 4.

Insert both of these values into the first equation:

x + y + z = 8 + 2sqr3

x + 4 + 4 = 8 + 2sqr3

x + 8 = 8 + 2sqr3

x = 2sqr3

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Hello!

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I hope this helps!

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Section B: Multiples and factors 1. Why is the number 17 classified as a prime number? ​
12345 [234]
17 is a prime number because it’s only divisible by 1 and it’s self, so it only has 2 factors.
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Paladinen [302]
Your question is incomplete.

If you want me to tell the ratio, its 3:2
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3 years ago
three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal
Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

=     x + x + (x + \frac{6}{5}) = \frac{27}{4}

=     3x + \frac{6}{5} = \frac{27}{4}

=     3x = \frac{27}{4} - \frac{6}{5}

( let's take the LCM of 4 and 5 = 20

=     3x = \frac{135}{20} - \frac{24}{20}

=     3x = \frac{111}{20}

=       x = \frac{111}{20} ÷ \frac{3}{1} = \frac{111}{20} × \frac{1}{3} = \frac{37}{20}

So, the weight of the equal bags are \frac{37}{20} and the weight of the third bag ( heavy one ) is \frac{37}{20} + \frac{6}{5} = \frac{37}{20} + \frac{24}{20} = \frac{61}{20}

1st bag =     \frac{37}{20} kg

2nd bag =  \frac{37}{20} kg

3rd bag =   \frac{61}{20} kg

Hope it helps...

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3 years ago
I WILL AWARD BRAINLIEST!! PLEASE HELP!!
Sergeeva-Olga [200]

xy \:  = product \\ xn \times 2y = 2nxy \\

the product will increase by 2n

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