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3 years ago

A jeweler is making a triangular pendant. He has two sides of length 23 mm and 31 mm. What are the

Mathematics

1 answer:

denis-greek [22]3 years ago

3 0

Answer:

38.60mm

Step-by-step explanation:

Step one:

Given data

We are given that the dimension of the triangles are length 23 mm and 31 mm

Let us assume that the triangle is a right angle triangle

Step two:

Applying the Pythagoras theorem we can find the third as

$z^2= x^2+y^2\\\\z^2= 31^2+23^2\\\\z^2= 961+529\\\\z^2= 1490\\\\$

square both sides

z= √ 1490

z= 38.60mm

Hence a possible dimension of the third side is 38.60mm

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The volume of the region R bounded by the x-axis is: $\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}$

<h3>What is the volume of the solid revolution on the X-axis?</h3>

The volume of a solid is the degree of space occupied by a solid object. If the axis of revolution is the planar region's border and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.

In the graph, the given straight line passes through two points (0,0) and (2,8).

Therefore, the equation of the straight line becomes:

$\mathbf{y-y_1 = \dfrac{y_2-y_1}{x_2-x_1}(x-x_1)}$

where:

(x₁, y₁) and (x₂, y₂) are two points on the straight line

Thus, from the graph let assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8), we have:

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Now, our region bounded by the three lines are:

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Similarly, the change in polar coordinates is:

x = rcosθ,
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where;

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rcosθ = 2 i.e. r = 2/cosθ
rsinθ = 4(rcosθ) ⇒ tan θ = 4; θ = tan⁻¹ (4)

⇒ r = 0 to r = 2/cosθ
θ = 0 to θ = tan⁻¹ (4)

Then:

$\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^2 (rdr d\theta )}$

$\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}$

Learn more about the determining the volume of solids bounded by region R here:

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