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3 years ago

A jeweler is making a triangular pendant. He has two sides of length 23 mm and 31 mm. What are the

Mathematics

1 answer:

denis-greek [22]3 years ago

3 0

Answer:

38.60mm

Step-by-step explanation:

Step one:

Given data

We are given that the dimension of the triangles are length 23 mm and 31 mm

Let us assume that the triangle is a right angle triangle

Step two:

Applying the Pythagoras theorem we can find the third as

$z^2= x^2+y^2\\\\z^2= 31^2+23^2\\\\z^2= 961+529\\\\z^2= 1490\\\\$

square both sides

z= √ 1490

z= 38.60mm

Hence a possible dimension of the third side is 38.60mm

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Sin167cos107-cos167sin107

insens350 [35]

Sin 167 = 0.22495

cos 107 = -0.29237

cos 167 = -0.97437

sin 107 = 0.95630

(sin 167)(cos 107) - (cos 167)(sin 107)

(0.22495)(-0.29237) - ( -0.97437)(0.95630)

= 0.86602

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3 years ago

Jake wants to buy a skateboard. The one he is looking at cost $295. It is on sale for 35% off. How much will Jake save if he buy

Aleks [24]

Answer:

191.5

Step-by-step 103.5 explanation:

295 x 0.35(which is 35%) = 103.5

295 - 103.5 = 191.5

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3 years ago

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stiv31 [10]

Answer:

9 is the value of x.

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2 years ago

FIRST TO ANSWER GETS BRAINLYEST WHATEVER ITS CALLED, PLEASE I NEED THIS DONE TODAY. JUST LOOK AT THE PICTURE

chubhunter [2.5K]

Answer:

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3 years ago

The shape of the distribution of the time required to get an oil change at a 20 minute oil change facility. However, records ind

Katyanochek1 [597]

Answer:

For a mean oil change time of 20.51 minutes there would be a 10% chance of being at or below

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 21.3, \sigma = 3.9, n = 40, s = \frac{3.9}{\sqrt{40}} = 0.6166$

Treating this as a random sample, at what mean oil-change time would there be a 10% chance of being at or below?

This is the 10th percentile, which is X when Z has a pvalue of 0.1. So it is X when Z = -1.28.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$-1.28 = \frac{X - 21.3}{0.6166}$

$X - 21.3 = -1.28*0.6166$

$X = 20.51$

For a mean oil change time of 20.51 minutes there would be a 10% chance of being at or below

6 0

3 years ago