All categories

2 years ago

If fixed costs are 100, and variable costs are at 5 per unit, find the total cost when Q=10.

Mathematics

1 answer:

kompoz [17]2 years ago

6 0

The total cost when Q = 10 is $150

Step-by-step explanation:

Th equation y = mx + b represents any linear function, where

m is the unit rate
b is the fixed amount

∵ The fixed costs are $100

∵ The variable costs are $5 per unit

∵ There are Q units

- Represent the total cost by the function c(Q)

∴ c(Q) = 5 Q + 100, where c(Q) is the total cost of Q units

∵ c(Q) = 5 Q + 100

∵ Q = 10

- Substitute Q by 10

∴ c(10) = 5(10) + 100

∴ c(10) = 50 + 100

∴ c(10) = 150

The total cost when Q = 10 is $150

Learn more:

You can learn more about word problems in brainly.com/question/884169

#LearnwithBrainly

You might be interested in

Jim takes out a mortgage for 30 years at an interest rate of 2.49% and his monthly repayments are $986.50. What is the principal

Svetllana [295]

The principal loan amount will be 250000. P is denoted by the principal loan amount

<h3> What is the amount?</h3>

The complete repayment of money at the end of the period for which it was borrowed is referred to as the amount.

The given data in the problem is;

P is the principal loan amount

r is the rate of interest = 2.49%

n is the time period= of 30 years

The formula for the principal loan amount is found as;

$\rm P=M(1-(1+\frac{r}{12} )^{\frac{12}{n}$

$\rm P=986.50(1-(1+\frac{0.249}{12} )^{\frac{12}{30} }\\\\ P= 250000$

Hence the principal loan amount will be 250000.

To learn more about the amount, refer to the link;

brainly.com/question/12184047

#SPJ1

6 0

1 year ago

The Ambell Company uses batteries from two different manufacturers. Historically, 70% of the batteries are from manufacturer 1,

Sunny_sXe [5.5K]

Answer:

0.625

Step-by-step explanation:

Given :

Ambell company uses or procures batteries from two manufacturers.

The life of a battery in critical tool is at = 32 hours

Ambell uses 70% of its batteries from manufacturer 1 and out of that 90% batteries lasts for about 40 hours.

Similarly, 75% of the batteries procured from the manufacturer 2 lasts for about 40 hours.

Therefore, the probability that a battery is form manufacturer 1 is :

$\frac{0.4 \times 0.25}{(0.6 \times0.1)+(0.4 \times 0.25)}$

= 0.625

5 0

3 years ago

Complete the following exercises by applying polynomial identities to complex numbers. Factor x2 + 64. Check your work. Factor 1

Mumz [18]

$x^2+64=x^2-(8i)^2=(x-8i)(x+8i)$

$16x^2+49=(4x)^2-(7i)^2=(4x-7i)(4x+7i)$

$(x+9i)^2=x^2+2x\cdot9i+(9i)^2=x^2+18xi+81i^2=x^2+18xi-81=x^2-81+18xi$

$(x-2i)^2=x^2-2x\cdot2i+(2i)^2=x^2-4xi+4i^2=x^2-4xi-4=x^2-4-4xi$

$(x+(3+5i))^2=x^2+2x(3+5i)+(3+5i)^2\\\\=x^2+6x+10xi+3^2+2\cdot3\cdot5i+(5i)^2\\\\=x^2+6x+10xi+9+30i+25i^2=x^2+6x+10xi+9+30i-25\\\\=x^2+6x+10xi+30i-16=x^2+6x-16+(10x+30)i$

$Used:\\i^2=-1\\\\a^2-b^2=(a-b)(a+b)\\\\(a+b)^2=a^2+2ab+b^2$

4 0

3 years ago

Read 2 more answers

1/3into a percent and a decimal

jeka57 [31]

Answer:

33% or .33

Step-by-step explanation:

Divide 1/3 = .3333 (repeating). I would round to the nearest hundreths place:

1/3 = .33

For the precentage, multiple 0.33 by 100:

100 * 0.33 = 33%