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NemiM [27]
3 years ago
6

What is the answer to -3 to the second power + 4.6 times -0.1

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
8 0
The answer is -9.46 yeah i think thats correct
Novosadov [1.4K]3 years ago
4 0
The answer is 13.7 because 3 times 3 is 9 then You add 4.6 which would be 13.6 You change -0.1 to a positive so it would be be 13.6 plus 0.1 and it would equal 13.7
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7.7 times 10 to the 12th power
podryga [215]

That is 77 to the power of twelve which is 77x77x77x77x77x77x77x77x77x77x77x77.

Answer:43439888521963583647921

4 0
3 years ago
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What is the area of this figure?
alina1380 [7]

Answer:

48??

Step-by-step explanation:

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Ann, Chang, and Kareem sent a total of
Gnoma [55]

It is given in the question that

Ann, Chang, and Kareem sent a total of 89 text messages over their cell phones during the weekend. Ann sent 9 fewer messages than Chang. Kareem sent 3 times as many messages as Ann.

Let number of messages Chang sent be x. And Ann sent 9 fewer than Chang, so Ann sent (x-9) messages. And Kareem sent 3 times as many messages as Ann, so Kareem sent 3(x-9) messages.

And the total messages are 89. That is

x+x-9+3(x-9)=89

Combining like terms

x + x - 9 + 3x-27 =89
\\
5x -36=89
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8 0
3 years ago
Simplify completely..........​
vitfil [10]

Answer:

\frac{x}{x-1}

Step-by-step explanation:

\frac{3x^2 - 1}{x^2 - 1} - \frac{2x + 1}{x + 1}                                          [ \ x^ 2- 1 = (x-1)(x + 1) \ ]

= \frac{3x^2 - 1}{(x-1)(x  + 1 )} - \frac{2x + 1}{x + 1}\\\\=\frac{(3x^2 - 1)-(2x + 1)(x-1)}{(x + 1)(x-1)}                        [\ Taking \ LCM \  ]

= \frac{(3x^2 - 1)- (2x^2 - 2x + x - 1)}{(x+1)(x-1)}\\\\=\frac{3x^2 - 1 - 2x^2 + x + 1 }{(x+1)(x-1)}\\\\=\frac{x^2 +x}{(x+1)(x-1)}\\\\=\frac{x(x+1)}{(x+1)(x-1)}\\\\=\frac{x}{x-1}

<em><u>Finding LCM :</u></em>

Example :

                 \frac{1}{6} + \frac{1}{3}

6 = 2  x   3

3 = 1   x   3

                \frac{1}{2 \times 3} + \frac{1}{ 3} = \frac{1}{2 \times 3} + \frac{1 \times 2}{ 3 \times 2}  

[ To make the denominators same : the second fraction is multiplied and divided by 2 ]

Similarly :

 (x^2 - 1 ) = (x -1)(x+1)\\\\(x + 1)  = 1 \times (x + 1)

Same rule we applied : multiplied the numerator and denominator of the second term with ( x - 1 )

Therefore the second term becomes ,

                                       \frac{2x + 1}{x + 1} = \frac{(2x + 1)(x - 1)}{(x + 1)( x - 1)}

7 0
3 years ago
Match the graph with its equation.
Assoli18 [71]

Answer is x=-4 second choice

5 0
4 years ago
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