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3 years ago

6

What is the answer to -3 to the second power + 4.6 times -0.1

2 answers:

vagabundo [1.1K]3 years ago

8 0

The answer is -9.46 yeah i think thats correct

Novosadov [1.4K]3 years ago

4 0

The answer is 13.7 because 3 times 3 is 9 then You add 4.6 which would be 13.6 You change -0.1 to a positive so it would be be 13.6 plus 0.1 and it would equal 13.7

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What is the factor of 3x2-9x-12?<br> pleaseeee help me guys !!

8090 [49]

Answer:3x² - 9x - 12 =

3(x² - 3x - 4) =

3(x² + x - 4x - 4) =

3(x(x+1)-4(x+1)) =

3(x+1)(x-4)

Step-by-step explanation:

8 0

3 years ago

Even would be helpful if you just gave me the equation to solve it and I can do the rest. mart had a sale for labor day on DVD's

erastova [34]

x - price of a video tape

y - price of a DVD

$\left\{\begin{array}{ccc}2x+3y=134\\x+5y=179&|\text{subtract 5y from both sides}\end{array}\right\\\\\left\{\begin{array}{ccc}2x+3y=134\\x=179-5y&|\text{substitute to the first equation}\end{array}\right\\\\2(179-5y)+3y=134\qquad\text{use distributive property}\\\\(2)(179)+(2)(-5y)+3y=134\\\\358-10y+3y=134\qquad\text{subtract 358 from both sides}\\\\-7y=-224\qquad\text{divide both sides by (-7)}\\\\\boxed{y=32}\\\\\text{Put the value of y to the second equation}\\\\x=179-5(32)\\\\x=179-160\\\\\boxed{x=19}$

<h3>Answer: video tape cost $19 and DVD cost $32.</h3>

6 0

3 years ago

Problem 4: Solve the initial value problem

pishuonlain [190]

Separate the variables:

$y' = \dfrac{dy}{dx} = (y+1)(y-2) \implies \dfrac1{(y+1)(y-2)} \, dy = dx$

Separate the left side into partial fractions. We want coefficients a and b such that

$\dfrac1{(y+1)(y-2)} = \dfrac a{y+1} + \dfrac b{y-2}$

$\implies \dfrac1{(y+1)(y-2)} = \dfrac{a(y-2)+b(y+1)}{(y+1)(y-2)}$

$\implies 1 = a(y-2)+b(y+1)$

$\implies 1 = (a+b)y - 2a+b$

$\implies \begin{cases}a+b=0\\-2a+b=1\end{cases} \implies a = -\dfrac13 \text{ and } b = \dfrac13$

So we have

$\dfrac13 \left(\dfrac1{y-2} - \dfrac1{y+1}\right) \, dy = dx$

Integrating both sides yields

$\displaystyle \int \dfrac13 \left(\dfrac1{y-2} - \dfrac1{y+1}\right) \, dy = \int dx$

$\dfrac13 \left(\ln|y-2| - \ln|y+1|\right) = x + C$

$\dfrac13 \ln\left|\dfrac{y-2}{y+1}\right| = x + C$

$\ln\left|\dfrac{y-2}{y+1}\right| = 3x + C$

$\dfrac{y-2}{y+1} = e^{3x + C}$

$\dfrac{y-2}{y+1} = Ce^{3x}$

With the initial condition y(0) = 1, we find

$\dfrac{1-2}{1+1} = Ce^{0} \implies C = -\dfrac12$

so that the particular solution is

$\boxed{\dfrac{y-2}{y+1} = -\dfrac12 e^{3x}}$

It's not too hard to solve explicitly for y; notice that

$\dfrac{y-2}{y+1} = \dfrac{(y+1)-3}{y+1} = 1-\dfrac3{y+1}$

Then

$1 - \dfrac3{y+1} = -\dfrac12 e^{3x}$

$\dfrac3{y+1} = 1 + \dfrac12 e^{3x}$

$\dfrac{y+1}3 = \dfrac1{1+\frac12 e^{3x}} = \dfrac2{2+e^{3x}}$

$y+1 = \dfrac6{2+e^{3x}}$

$y = \dfrac6{2+e^{3x}} - 1$

$\boxed{y = \dfrac{4-e^{3x}}{2+e^{3x}}}$

7 0

2 years ago

What is the ratio<br> a million to one

Angelina_Jolie [31]

One milion is 1000 thousand or 1,000,000

so million:one is 1,000,000:1

7 0

3 years ago

Read 2 more answers

If 1/2 of 1 is 1/2 what is 1/2 of 2 3 and 4?

myrzilka [38]

1/2 of 2 is 1 .

1/2 of 3 is (1 and 1/2).

1/2 of 4 is 2 .

7 0

3 years ago

Read 2 more answers