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mina [271]
3 years ago
8

Help on # 2 please. Thank you!

Mathematics
1 answer:
Alenkasestr [34]3 years ago
3 0

Answer:

There are 9 boys in the choir

Step-by-step explanation:

To solve this, create two equivalent fractions with the information given

boys      3         x

------- = ------ = ------

girls       4         12

Then, cross-multiply

4x = 3(12)

4x = 36

x = 9

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Kenny's charges $8 per hour to babysit he wants to figure out how much money do you earn in a week which variable is needed to c
Korolek [52]

Answer:

H

Step-by-step explanation:

The amount of hours he has worked would be x 8$

3 0
3 years ago
The revenue, in dollars, of a company that makes toy cars can be modeled by the polynomial 3x2 + 4x – 60. The cost, in dollars,
Tems11 [23]

For this case we have the following quadratic functions:

Revenue: 3x ^ 2 + 4x - 60

Cost: 3x ^ 2 - x + 200

Then, we observe that the profit is given by the following mathematical relationship:

Profit = Revenue - Cost

Substituting values we have:

Profit = (3x ^ 2 + 4x - 60) - (3x ^ 2 - x + 200)

Making the corresponding calculations we have:

Profit = x ^ 2 (3-3) + x (4 + 1) + (-60-200)\\Profit = 5x - 260

Answer:

An expression that represents the profit is:

Profit = 5x - 260

4 0
3 years ago
Read 2 more answers
5k-2(3k + 4) = 5x + 4<br> help?
vazorg [7]
Use distributive property
5k - 6k -8 = 5x + 4
Combine like terms
-k - 8 = 5x + 4
add 8 to both sides
-k = 5x + 12
k = -5x- 12
4 0
2 years ago
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Find the volume of a cylinder with a diameter if 10 cm and a height of 10 cm?​
RideAnS [48]

Step-by-step explanation:

volume of cylinder=π(d/2)²h=π/4×10²×10=250πcm³

7 0
2 years ago
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In a parallelogram ABCD point K belongs to diagonal BD so that BK:DK=1:4. If the extension of AK meets BC at point E, what is th
olya-2409 [2.1K]

Answer:

\frac{BE}{EC} =\frac{1}{3}

Step-by-step explanation:

In the diagram below we have

ABCD is a parallelogram. K is the point on diagonal BD, such that

\frac{BK}{CK} =\frac{1}{4}

And AK meets BC at E

now in Δ AKD and Δ BKE

∠AKD =∠BKE                ( vertically opposite angles are equal)

since BC ║ AD and BD is transversal

∠ADK = ∠KBE     ( alternate interior angles are equal )

By angle angle (AA) similarity theorem

Δ ADK  and Δ EBK are similar

so we have

\frac{AD}{BE} =\frac{DK}{BK}

\frac{AD}{BE} =\frac{4}{1}

\frac{BC}{BE}=\frac{4}{1}     ( ABCD is parallelogram so AD=BC)

\frac{BE+EC}{BE}=\frac{4}{1}         ( BC= BE+EC)

\frac{BE}{BE} +\frac{EC}{BE}=\frac{4}{1}

1+\frac{EC}{BE}=4

\frac{EC}{BE}=3  ( subtracting 1 from both side )

\frac{EC}{BE}=\frac{3}{1}

taking reciprocal both side

\frac{BE}{EC} =\frac{1}{3}


8 0
3 years ago
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