Answer:
i don't know
Step-by-step explanation:
Answer:
Step-by-step explanation:
15/2 = 7.5 and (7.5)^2 = 56.25 so
x^2 + 15x + 56.25 = 49 + 56.25
x^2 + 15x + 56.25 = 105.25.
<h2><u>
Answer with explanation</u>
:</h2>
Let 
be the distance traveled by deluxe tire .
As per given , we have
Null hypothesis : 
Alternative hypothesis : 
Since 
is left-tailed and population standard deviation is known, thus we should perform left-tailed z-test.
Test statistic : 
where, n= sample size
= sample mean
= Population mean
=sample standard deviation
For 
, we have
By using z-value table,
P-value for left tailed test : P(z≤-2.23)=1-P(z<2.23) [∵P(Z≤-z)=1-P(Z≤z)]
=1-0.9871=0.0129
Decision : Since p value (0.0129) < significance level (0.05), so we reject the null hypothesis .
[We reject the null hypothesis when p-value is less than the significance level .]
Conclusion : We do not have enough evidence at 0.05 significance level to support the claim that t its deluxe tire averages at least 50,000 miles before it needs to be replaced.
Answer:
Option b) 6-10 lbs
Step-by-step explanation:
Given that X, the weight of toy American Eskimo dog has mean of 8 pounds with a standard deviation of 1 pound
For 95% of the dogs according to normal distribution would lie between 2 std deviations on either side of the mean.
i.e. lower bound= Mean- 2 std deviation = 8-2 =6
Upper bound = Mean +2 std dev = 8+2 =10
Hence range of weights would be
6-10 lbs
Option b is the answer
Answer:
It is B, D and F
Step-by-step explanation:
because red 2 is very specific and not putting it back in the deck makes it independent
