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MAVERICK [17]
2 years ago
7

IF YOUR GOOD AT MATH THEM PLEASE ANSWER THIS !

Mathematics
2 answers:
baherus [9]2 years ago
6 0

x+5+x+x+5=4x+10

Answer:

4x+10

Step-by-step explanation:

x+5+x+x+5=4x+10

GrogVix [38]2 years ago
5 0
Answer ;
D/4
4x+10
Hope this helps!! (:
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58,967 grams (Use an online measurement converter)

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What is a nonagon with a perimeter of 144 inches?
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Answer: Regular nonagon

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Two cars are traveling along the same highway. The distance, d, in miles, from San Francisco after h hours spent driving is desc
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The answers are A,D,F
5 0
3 years ago
The monthly demand equation for an electric utility company is estimated to be p equals 59 minus (10 Superscript negative 5 Base
mestny [16]

Answer:

a) The price that maximizes profit is p =$43.

b) The utility shouldn't pass all this increase on the consumers because this would mean a decrease in the profits. They should pass only $7 to consumers price.

Step-by-step explanation:

We have an electric utility company which has a demand function defined by:

p=59-10^{-5}x

where p is the price and x is the the energy in thousands of kWh.

The cost of the company is defined as:

C(x)=3\cdot 10^6+27x

We have to calculate the price that maximizes the utility's profit R(x).

We can define the profit as:

R(x)=p\cdot x-C=(59-10^{-5}x)\cdot x-(3\cdot 10^6+27x)\\\\R(x)=-10^{-5}x^2+(59-27)x-3\cdot10^6\\\\R(x)=-10^{-5}x^2+32x-3\cdot10^6.

To maximize R, we have to derive it and equal to zero

\dfrac{dR}{dx}=0\\\\\\\dfrac{dR}{dx}=-2\cdot10^{-5}x+32=0\\\\\\x=(32/2)\cdot 10^5=16\cdot 10^5=1.6\cdot 10^6

The price that maximizes the profit is then:

p=59-10^{-5}x=59-10^{-5}(16\cdot 10^5)=59-16=43

b) When the unit cost rise from $27 to $41, the utility profit function changes.

We have to calculate the new price that maximizes profit, and then we will know if the rise in cost was transferred to price completely.

The new profit function is:

R(x)=p\cdot x-C=(59-10^{-5}x)\cdot x-(3\cdot 10^6+41x)\\\\R(x)=-10^{-5}x^2+(59-41)x-3\cdot10^6\\\\R(x)=-10^{-5}x^2+18x-3\cdot10^6

To maximize R, we have to derive it and equal to zero

\dfrac{dR}{dx}=0\\\\\\\dfrac{dR}{dx}=-2\cdot10^{-5}x+18=0\\\\\\x=(18/2)\cdot 10^5=9\cdot 10^5

We calculate the new price as:

p=59-10^{-5}x=59-10^{-5}(9\cdot 10^5)=59-9=50

The new price is $7 dollars above the previous maximizing price, so the rise in unit cost is only transferred 50% to the price.

The utility shouldn't pass all this increase on the consumers because this would mean a decrease in the profits. They should pass only $7 to consumers price.

4 0
3 years ago
Round 3.06735995694 to the nearest millionth.
makvit [3.9K]
The "th" family is a little confusing but you look and find the millionth place.  It's basically backwards.  

0 is tenths
6 is hundredths
7 is thousandths
3 is ten-thousandths
5 is hundred-thousands 
9 is millionths 

the number next to it is a 9 (rule round up if it's greater than 5)  

since the number is a 9 you have to round up even one more making the 5 a 6 

3.06736
8 0
3 years ago
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