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mafiozo [28]
2 years ago
15

What does a 45 degree angle look like

Mathematics
1 answer:
Stolb23 [73]2 years ago
6 0
This is what a 45 degree angle looks like.
Good luck!

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The graphs below were created by an advertising agency for the computer store TechPlus to show its average price on laptops and
Nostrana [21]

Answer:

Step-by-step explanation:

7 0
2 years ago
Marc wants to guess how many marbles are in a box that has a height of 18 inches. He calculates that there are 32 marbles in a h
Rainbow [258]

So every 5 inches in height, there are 32 marbles. You want to know how many marbles there are per 18 inches in height.

\frac{32}{5} = \frac{x}{18}

To get from 5 to 18, you multiply by 3.6.

Do the same thing to the numerator; 32 × 3.6 = 115.2.

Since 0.2 marbles is no marbles, you round down.

There are 115 marbles in the box.

♡ Hope this helps! ♡

❀ 0ranges ❀

8 0
2 years ago
You have P = 472 feet of fencing to enclose a rectangular plot that borders on a river. If you do not fence the side along the r
Ray Of Light [21]
The width would be 236 and the lengths would be 118

Use the equations 2L+W=472 and W*L=MAX
Change the first equation to W=472-2L and plug this into the other equation
(472-2L)(L)=MAX
472L-2L^2=M (take derivative)
472-4L=0 (set to 0 to find the max value)
4L=472 
L=118 
Plug into original to get W=236

Hope this helps!
4 0
3 years ago
Please help solve this system of equations
stepan [7]

Make a substitution:

\begin{cases}u=2x+y\\v=2x-y\end{cases}

Then the system becomes

\begin{cases}\dfrac{2\sqrt[3]{u}}{u-v}+\dfrac{2\sqrt[3]{u}}{u+v}=\dfrac{81}{182}\\\\\dfrac{2\sqrt[3]{v}}{u-v}-\dfrac{2\sqrt[3]{v}}{u+v}=\dfrac1{182}\end{cases}

Simplifying the equations gives

\begin{cases}\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81}{182}\\\\\dfrac{4\sqrt[3]{v^4}}{u^2-v^2}=\dfrac1{182}\end{cases}

which is to say,

\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81\times4\sqrt[3]{v^4}}{u^2-v^2}

\implies\sqrt[3]{\left(\dfrac uv\right)^4}=81

\implies\dfrac uv=\pm27

\implies u=\pm27v

Substituting this into the new system gives

\dfrac{4\sqrt[3]{v^4}}{(\pm27v)^2-v^2}=\dfrac1{182}\implies\dfrac1{v^2}=1\implies v=\pm1

\implies u=\pm27

Then

\begin{cases}x=\dfrac{u+v}4\\\\y=\dfrac{u-v}2}\end{cases}\implies x=\pm7,y=\pm13

(meaning two solutions are (7, 13) and (-7, -13))

8 0
2 years ago
If 10^x = 5, what is x?
Valentin [98]

Answer:

x=0.69897009

Step-by-step explanation:

expand by logarithms

10^x=5

=log(10^x)=log(5)

=x log(10)=log (5)

log base 10 of 10 is 1

x.l =log(5)

multiple bothside by 1

x=log(5)

x=0.6989709

6 0
3 years ago
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