Let , so that differentiating both sides wrt gives
If and , the above reduces to
This is the slope of the tangent line, which has equation
<h3>
Answer: Choice A</h3>
- Domain: x > 4
- Range: y > 0
========================================================
Explanation:
We want to avoid having a negative number under the square root. Solving leads to
So it appears the domain could involve x = 4 itself; however, if we tried that x value, then we'd get a division by zero error.
So in reality, the domain is x > 4.
-------------
The range of y = sqrt(x) is the set of positive real numbers. So y > 0 is the range for this equation. Shifting left and right does not affect the range, so the range of y = sqrt(x-4) is also y > 0.
We are dividing a positive number (3) over some positive number in the denominator. Overall, the expression is positive because positive/positive = positive.
Therefore, the range of the given equation is y > 0
-------------
The graph is shown below. We have a vertical asymptote at x = 4 and a horizontal asymptote at y = 0. The green curve is fenced in the upper right corner (northeast corner).
Create a system of equations
x + y = 123
5x + y = 343
I use substitution
y = 123 - x
5x + 123 - x = 343
4x + 123 = 343
4x = 220
x = 55
Plug in
x + y = 123
55 + y = 123
y = 68
Check
5x + y = 343
5(55) + 68 = 343
275 + 68 = 343
343 = 343
end behavior is affect by the exponent and whether its negative or positive
y = y^3 starts negative from -∞ to 0 the from 0 to +∞ goes positive
since this equation is negative its switched
-∞ to 0 its positive x>0
0 to +∞ is negative x<0
The distance between starting and ending point is 34 miles.
Step-by-step explanation:
Given,
Car moves 16 miles to north then 30 mile to east.
It forms a right angle triangle.
The straight line distance from starting to ending point represents hypotenuse.
To find the distance between starting and ending point.
Formula
By <em>Pythagoras theorem,</em>
h² = b²+l² where h is the hypotenuse, b is base and l is the another side.
Taking, b=16 and l=30 we get,
h² = 16²+30²
or, h =
or, h = = 34
Hence,
The distance between starting and ending point is 34 miles.