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mylen [45]
3 years ago
6

A yardstick placed perpendicular to the ground casts a 4 foot shadow. At the same time, a grain silo casts a 34 foot shadow. Wri

te a proportion you can use to find the height of the silo
Mathematics
1 answer:
kobusy [5.1K]3 years ago
4 0
There is a 30 ft difference how can you not tell
You might be interested in
How is the series 5+11+17…+251 represented in summation notation?
NISA [10]

Answer:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

Step-by-step explanation:

Given:

  • Series 5+11+17+...+251

To find:

  • Summation notation of the given series

Summation Notation:

\displaystyle \large{\sum_{k=1}^n a_k}

Where n is the number of terms and \displaystyle \large{a_k} is general term.

First, determine what kind of series it is, there are two main series that everyone should know:

  • Arithmetic Series

A series that has common difference.

  • Geometric Series

A series that has common ratio.

If you notice and keep subtracting the next term with previous term:

  • 11-5 = 6
  • 17-11 = 6

Two common difference, we can in fact say that the series is arithmetic one. Since we know the type of series, we have to find the number of terms.

Now that brings us to arithmetic sequence, we know that first term is 5 and last term is 251, we’ll be finding both general term and number of term using arithmetic sequence:

<u>Arithmetic Sequence</u>

\displaystyle \large{a_n=a_1+(n-1)d}

Where \displaystyle \large{a_n} is the nth term, \displaystyle \large{a_1} is the first term and \displaystyle \large{d} is the common difference:

So for our general term:

\displaystyle \large{a_n=5+(n-1)6}\\\displaystyle \large{a_n=5+6n-6}\\\displaystyle \large{a_n=6n-1}

And for number of terms, substitute \displaystyle \large{a_n} = 251 and solve for n:

\displaystyle \large{251=6n-1}\\\displaystyle \large{252=6n}\\\displaystyle \large{n=42}

Now we can convert the series to summation notation as given the formula above, substitute as we get:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

5 0
3 years ago
Solving quadratics equations by taking square root
Novay_Z [31]
#6
x^2 = 1
x = - 1 and x = + 1

#7
a^2 + 1 = 19
a^2 =18
a^2 =√ 9 <span>√ 2
a = + 3</span>√ 2 and a = - 3<span>√ 2</span>
4 0
4 years ago
Pls find the blank space. <br><br>the first answer will get marked brainliest​
True [87]

Step 1

Anything divided by one gives itself.

\frac{1}{8}=-8\text{ and }\frac{-8}{1}=\frac{-12}{48}

8

1

=−8 and

1

−8

=

48

−12

Step 2

Convert -8−8 to fraction -\frac{64}{8}−

8

64

.

\frac{1}{8}=-\frac{64}{8}\text{ and }\frac{-8}{1}=\frac{-12}{48}

8

1

=−

8

64

and

1

−8

=

48

−12

Step 3

Compare \frac{1}{8}

8

1

and -\frac{64}{8}−

8

64

.

\text{false}\text{ and }\frac{-8}{1}=\frac{-12}{48}false and

1

−8

=

48

−12

Step 4

Anything divided by one gives itself.

\text{false}\text{ and }-8=\frac{-12}{48}false and −8=

48

−12

Step 5

Reduce the fraction \frac{-12}{48}

48

−12

to lowest terms by extracting and canceling out 1212.

\text{false}\text{ and }-8=-\frac{1}{4}false and −8=−

4

1

Step 6

Convert -8−8 to fraction -\frac{32}{4}−

4

32

.

\text{false}\text{ and }-\frac{32}{4}=-\frac{1}{4}false and −

4

32

=−

4

1

Step 7

Compare -\frac{32}{4}−

4

32

and -\frac{1}{4}−

4

1

.

\text{false}\text{ and }\text{false}false and false

Step 8

The conjunction of \text{false}false and \text{false}false is \text{false}false.

\text{false}false

Hint

Do the arithmetic.

Solution

\text{false}false

4 0
2 years ago
Read 2 more answers
Which of the following is an equation of the line that passes through the point (5/3,-6) and has a slope of -3/4
ratelena [41]

Line through (a,b) with slope m is

y - b = m(x -a)

Here that's line through (a,b)=(5/3, -7) with slope m=-3/4

y - -7 = (-3/4) (x - 5/3)

Solve for y,

y + 28/4 = (-3/4) x + 5/4

y = (-3/4) x - 23/4

Look at the choices.

Answer: D

6 0
3 years ago
Does anyone know the answer to this?
Rainbow [258]

Answer:

the last one

Step-by-step explanation:

Two lines will be parallel when their slopes are equal, and two lines will be perpendicular when their slopes are negative reciprocals of each other. Our slopes for these two equations are the coefficient for the x value. Both slopes are equal so these lines are parallel.

4 0
3 years ago
Read 2 more answers
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