F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
Answer:
55M
Step-by-step explanation:
Answer:
The value of angle B is 33.69°
Step-by-step explanation:
You can find out using Tangent Rule, tanθ = oppo./adj. where opposite and adjacent are the length of triangle :
oppo. = AC = 6 units
adj. = BC = 9 units
θ = ∠B
tan ∠B = AC/BC
tan ∠B = 6/9
∠B = tan^(-1) (6/9)
= 33.69° (near. hundredth)
I don’t feel like doing school and I keep getting distracted by this app
Answer:
Andrew has $15 left over each month
Step-by-step explanation:
Inflows=$240+$60=$300/mo.
Outflows=$170+$70+45=$285/mo.
Inflows-Outflows=left over
$300-$285=$15
