<h3>Given</h3>
- room height is x feet
- room length is 3x feet
- room width is 3x feet
- a door 3 ft wide by 7 ft tall
<h3>Find</h3>
- The net area of the wall, excluding the door
<h3>Solution</h3>
The area of the wall, including the door, is the room perimeter multiplied by the height of the room. The room perimeter is the sum of the lengths of the four walls.
... gross wall area = (3x +3x +3x +3x)·x = 12x²
The area of the door is the product of its height and width.
... door area = (7 t)×(3 ft) = 21 ft²
Then the net wall area, exclusive of the door is ...
... net wall area = gross wall area - door area
... net wall area = 12x² -21 . . . . square feet
Is there a question or is this it ?
it basically answers itself because 2 times 3 is 6
I believe the correct expression is: <span>11.50(1.083)^t where t is the time.
Now, we are given that the average price of the ticket is $11.5
The given expression means that this average value is dependent on the variable t. Therefore, the average price of the ticket increases exponentially with the time with the rate of growth equals 1.083
Now, to better understand this, we will get the price of the ticket at different times:
At t = 1: price = </span><span>11.50(1.083)^1 = $12.4545
At t = 2: price = </span><span>11.50(1.083)^2 = $13.4882235
At t = 3: price = </span><span>11.50(1.083)^3 = $14.60774605
We can notice that the price of the ticket increases exponentially as the time increases.
Hope this helps :)</span>
