Solution: We are given:

Let
be the weight (oz) of laptop
We have to find 
To find the this probability, we need to find the z score value.
The z score is given below:



Now, we have to find 
Using the standard normal table, we have:

0.9236 or 92.36% of laptops are overweight
Answer:
If Jeff is types 5 pages at 600 words per page, then he types 3,000 words (5 x 600).
So, if Jeff started typing at 8:15 am, he'd finish at 9:30 am.
Step-by-step explanation:
Answer:
do u even still need the answer its been aweek since you asked it and it was due that same day
Step-by-step explanation:
Answer:
hope it helps plz mark me brainliest..
Step-by-step explanation:
15.5 times 5.26 is 81.53 and 80 is closest to that so D