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allochka39001 [22]
3 years ago
5

Simplify: x^d • x ^18

Mathematics
2 answers:
natta225 [31]3 years ago
5 0

Answer:

x^(d+18)

Step-by-step explanation:

using the law of indices

you must add the powers

Triss [41]3 years ago
3 0

Answer:

{x}^{d + 18}

Step-by-step explanation:

  • \sf{x^d.x^{18}  }

  • \sf{ x^{d+18}  }
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abruzzese [7]

Answer:

First solve for x

then substitute

Step-by-step explanation:

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6(\frac{x+3}{3}=\frac{y+2}{2})

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If \frac{x+3}{3}= \frac{y+2}{2} then \frac{x}{3} =

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2 years ago
Graph the following quadratic equation<br> f (x) = x² - 4x + 3
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Step-by-step explanation:

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2 years ago
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4 0
2 years ago
Find the mass of the solid paraboloid Dequals=​{(r,thetaθ​,z): 0less than or equals≤zless than or equals≤8181minus−r2​, 0less th
Lubov Fominskaja [6]

Answer:

M = 5742π  

Step-by-step explanation:

Given:-

- Find the mass of a solid with the density ( ρ ):

                             ρ ( r, θ , z ) = 1 + z / 81

- The solid is bounded by the planes:

                             0 ≤ z ≤ 81 - r^2

                             0 ≤ r ≤ 9

Find:-

Find the mass of the solid paraboloid

Solution:-

- The mass (M) of any solid body is given by the following triple integral formulation:

                           M = \int \int \int {p ( r ,theta, z)} \, dV\\\\

- We can write the above expression in cylindrical coordinates:

                           M = \int\limits\int\limits_r\int\limits_z {r*p(r,theta,z)} \, dz.dr.dtheta \\\\M = \int\limits\int\limits_r\int\limits_z {r*[ 1 + \frac{z}{81}] } \, dz.dr.dtheta\\\\

- Perform integration:

                           M = \int\limits\int\limits_r{r*[ z + \frac{z^2}{162}] } \,|_0^8^1^-^r^2 dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{(81-r^2)^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{6561 -162r + r^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + 40.5 -r +\frac{r^2}{162} ] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{[ 121.5r-r^2 -\frac{161r^3}{162} ] } \, dr.dtheta\\\\

                           M = 2*\int\limits_0^\pi {[ 121.5r^2-r^3 -\frac{161r^4}{162} ] } |_0^6 \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 121.5(6)^2-(6)^3 -\frac{161(6)^4}{162} ] }  \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 4375-216 -1288] }  \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 2871] }  \, dtheta\\\\M = 5742\pi  kg              

- The mass evaluated is M = 5742π                      

8 0
3 years ago
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lyudmila [28]

Answer:

1/6

Step-by-step explanation:

2/3 times 1/4 is 2/12. 2/12 simplified is 1/6, so 1/6 is your answer.

7 0
3 years ago
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