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Norma-Jean [14]
3 years ago
12

Help meeeee!!!!!! Please

Mathematics
1 answer:
Over [174]3 years ago
6 0

Answer:

-1/11

Step-by-step explanation:

if this is one of the answer choices.

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Solve using the Quadratic Formula:<br><br> 3x2−12x−9=0
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Answer:

x²+x-1=0

3x²-12x-9=0

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What is equivalent to the following expression select all that apply.
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C.6 3 becaue im trying to get point dont lissten to me

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X+1 to the second power
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Use inductive reasoning to find the next term in this sequence 2,3,5,9,17. Then explain the rule for the pattern.
NISA [10]

We have been given the sequence 2,3,5,9,17.

We can write the terms of this sequence as

2=2^0+1\\&#10;3=2^1+1\\&#10;5=2^2+1\\&#10;9=2^3+1\\&#10;17=2^4+1\\

From the above term we can see that for the first term we take exponent 0 on 2 and then add 1 .

For second term we take exponent 1 on 2 and then add 1 .

For third term we take exponent 2 on 2 and then add 1 .

Using this fact for the next term of the sequence i.e. 6th term, we can take exponent 5 on 2 and then add 1 .

Therefore, next term of the sequence is given by

2^5+1\\&#10;=32+1\\&#10;=33

Therefore, the next term is 33.

Using the above facts, the pattern is given by

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7 0
3 years ago
find the Taylor Series for tan−1(x) based at 0. Give your answer using summation notation and give the largest open interval on
enyata [817]

Let f(x)=\tan^{-1}x. Then f'(x)=\frac1{1+x^2}. Note that f(0)=0.

Recall that for |x|, we have

\displaystyle\frac1{1-x}=\sum_{n\ge0}x^n

This means that for |-x^2|=|x|^2, or -1, we have

\displaystyle f'(x)=\frac1{1+x^2}=\frac1{1-(-x^2)}=\sum_{n\ge0}(-x^2)^n=\sum_{n\ge0}(-1)^nx^{2n}

Integrate the series to get

f(x)=f(0)+\displaystyle\sum_{n\ge0}\frac{(-1)^n}{2n+1}x^{2n+1}

\implies\tan^{-1}x=\displaystyle\sum_{n\ge0}\frac{(-1)^n}{2n+1}x^{2n+1}

6 0
3 years ago
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