sorry
look im trying to finish a challange u need premium if your going toask that big of a quietion my dude/dudet
You can convert (1/625) to an exponent, and it would be ideal to have 5 as the base of it because you want your log base to cancel it out. what i usually do in this case is just test out 5^1, 5^2, etc until i find one that matches the number i need. in this case because the number you're trying to work with is a small fraction, you'll want to use NEGATIVE exponents so it'll create a fraction instead of a large whole number:
5^-1 = 1/5
. . . keep trying those. . .
5^-4 = 1/625
so, because they're equal to one another, it'll be waaay easier after you substitute 5^-4 in place of 1/625
x = log₅ 5⁻⁴
log base 5 of 5 simplifies to 1. subbing in the 5^-4 gets rid of the log for you altogether, and your -4 exponent drops down:
x = -4 is your answer
if the exponent dropping down doesn't make sense to you, you can think of it in another way:
x = log₅ 5⁻⁴
expand the expression so that the exponent moves in front of the log function:
x = (-4) log₅ 5
then, still, log base 5 of 5 simplifies to 1, so you're left with:
x = (-4)1 or x = -4
It's a kite or a rhombus.
The coefficient is 4
The constants are 2 and 3
Here's what i did:
I broke down the fraction entirely.
3 / 5 = 6 / 10
divide 6 by two and divide 18 by two. This makes 3 / 10 = 9.
divide 3 by three and 9 by three, making 1 / 10 = 3.
if you need 7 / 10 of the number (30) then do 3*7.
The answer is 21.
