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Rzqust [24]
2 years ago
6

What are the end behaviors of f(x)=-2(x-2)5

Mathematics
1 answer:
Alborosie2 years ago
8 0

Answer:c

Step-by-step explanation:

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What is an equation of the line that passes through the points (1,6) and (1, 2)?
tangare [24]

Answer:

x=1

Step-by-step explanation:

Since both lines have 1 as it x value, x=1 is the line

4 0
2 years ago
X²-7x+14 what is the answer?
Furkat [3]

Answer: X intercepts none Y intercepts (0,14)

Step-by-step explanation:

6 0
2 years ago
The coordinate −6 has a weight of 3, and the<br> coordinate 2 has a weight of 1
Damm [24]

The weight average of the coordinates is -4

<h3>How to determine the weight average?</h3>

The complete question is given as:

The coordinate -6 has a weight of 3 and the coordinate 2 has a weight of 1. And we need to calculate the weight average

The given parameters are:

  • Coordinate -6 has a weight of 3
  • Coordinate 2 has a weight of 1.

The weight average is then calculated as:

Weight average = Sum of (Weigh * Coordinate)/Sum of Weights

So, we have:

Weight average = (-6 * 3 + 2 * 1)/(3 +1)

Evaluate the products

Weight average = (-18 + 2)/(3 +1)

Evaluate the sum

Weight average = -16/4

Evaluate the quotient

Weight average = -4

Hence, the weight average of the coordinates is -4

Read more about average at

brainly.com/question/20118982

#SPJ1

<u>Complete question</u>

The coordinate -6 has a weight of 3 and the coordinate 2 has a weight of 1. Calculate the weight average

4 0
2 years ago
Graph x^2+60x+256in^2​
Softa [21]

Answer:

44

Step-by-step explanation:

there you goooooo oooooooooooooooooo

8 0
3 years ago
A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along
mina [271]

Answer:

The tip of the man shadow moves at the rate of \frac{20}{3} ft.sec

Step-by-step explanation:

Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

From the figure, we can form a proportion.

\frac{y - x}{y} = \frac{6}{15}

Cross multiplying, we get

15(y -x) = 6y

15y - 15x = 6y

15y - 6y = 15x

9y = 15x

y = \frac{15x}{9\\} y = \frac{5x}{3}

We need to find rate of change of the shadow. So we need to differentiate y with respect to the time (t).

\frac{dy}{t} = \frac{5}{3} \frac{dx}{dt} ----(1)

We are given \frac{dx}{dt} = 4 ft/sec. Plug in the equation (1), we get

\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

7 0
3 years ago
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