Part A
The graph is shown below as an attached image.
The diagram shows a straight line that goes through the two points (0,-3) and (1, -5)
I'm using GeoGebra to graph the line.
side note: (0, -3) is the y intercept which is where the graph crosses the y axis.
==================================================
Part B
Answer is choice 2
The graph can be written in the form y = mx+b, so it is linear
In this case, m = -2 is the slope and b = -3 is the y intercept
We can write the slope as m = -2 = -2/1. This tells us that we can move down 2 units and then over to the right 1 units to get from point to point. This process of "down 2, over to the right 1" happens when moving from point A to point B in the diagram below.
We know that
if two lines are perpendicular
then
the slopes
m1*m2=-1
step 1
find the slope AB
A (0,2)
B (-3,-3)
m=(y2-y1)/(x2-x1)-----> m=(-3-2)/(-3-0)-----> m=-5/-3----> m1=5/3
step 2
find the slope CD
C (-4,1)
D (0,-2)
m=(y2-y1)/(x2-x1)-----> m=(-2-1)/(0+4)-----> m=--3/4----> m2=-3/4
step 3
multiply mi*m2
(5/3)*(-3/4)-----> -15/12
so
15/12 is not -1
therefore
AB is not perpendicular to CD
Answer:
b) -4
Step-by-step explanation:
Well your at 2 and going to -2 so on a number line you be going back or left.
Going two left gets you to zero and going two more get you -2. So in total you went back four and that be represented as -4.
Can you add the options?
Also since the options aren't there I'll just help set up.
So angle 1 and angle 3 add up to 90 degrees. Angle 1 and Angle 2 are equal so whatever option has something around those lines is correct.
It is 12 since 1/6=6^-1=6
implies 2*6=12
