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Free_Kalibri [48]
3 years ago
11

Does someone know this ??

Mathematics
2 answers:
Misha Larkins [42]3 years ago
7 0
The scale factor is 1/5
Liula [17]3 years ago
5 0

the scale factor would be 1/5 because the side length of 4 for the second triangle is 1/5 of the side length of the first triangle which is 20
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Prove that<br>{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)
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First, expand the terms inside the bracket you will get

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( 4 \tan(x)  \sin(x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

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16 \tan {}^{2} (x) (1 -  \cos {}^{2} (x) ) = 16 (\tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan {}^{2} (x)  -   \frac{  \sin {}^{2} (x) \cos {}^{2} ( {x}^{} )  }{ \cos {}^{2} (x) }

16( \tan {}^{2} (x)  -  \sin {}^{2} (x) ) = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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              x³ + 6x²

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                    <u> +       +     </u>

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                                14x + 84

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                                     0

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Answer:

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Step-by-step explanation:

When you graph the given equation on the given graph, you find the lines intersect at (-8, -6).

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