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yaroslaw [1]
3 years ago
11

A scientist in the lab is measuring a beetle to be 32 millimeters long, how much is that in meters?

Mathematics
2 answers:
Fudgin [204]3 years ago
6 0
The answer is .032 meters.
RUDIKE [14]3 years ago
5 0
32 millimeters = 0.032 meters
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Divide and round to the nearest hundredths place.<br> 2.75 ÷ 6
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<span>2.75 ÷ 6
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PLZ HELP ME ILL MARK BRAINLEIST!!!!!!!!!!!!
FrozenT [24]

Answer:

B. ∠1 and ∠8 are parallel

Step-by-step explanation:

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2 years ago
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HELP ASAP TIMED !!!! What is the exact value of cos(c + d), given Sine c = StartFraction 24 Over 25 EndFraction for c in Quadran
Keith_Richards [23]

9514 1404 393

Answer:

  D

Step-by-step explanation:

In the second quadrant, ...

  c = 180° -arcsin(24/25) ≈ 106.26°

In the third quadrant, ...

  d = 360° -arccos(-3/4) ≈ 221.41°

Then cos(c+d) = cos(327.67°) ≈ 0.84498

This is a positive irrational number, greater than 21/100, so the only reasonable choice is the last one:

  \dfrac{21+24\sqrt{7}}{100}\approx 0.84498

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Perhaps you want to work this out using the trig identities.

  cos(c) = -√(1 -sin(c)²) = -7/25

  sin(d) = -√(1 -cos(d)²) = -(√7)/4

Then the desired cosine is ...

  cos(c+d) = cos(c)cos(d) -sin(c)sin(d)

  cos(c+d) = (-7/25)(-3/4) -(24/25)(-√7/4)

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2 years ago
How do you find surface area ? i don't remember. also new friends :) ?
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Answer:

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Step-by-step: The surface area is the number of square units that fit into the square. As shown in the picture, the surface area of this square is 16 total square units. With a rectangle and square we can also get the surface area by multiplying width (W) x length (L).tep explanation:

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3 years ago
Find -7a-6B (Picture provided)
sertanlavr [38]

Answer:

Option c

-7A-6B=\left(\begin{array}{ccc}40&-106&-32\\-46&43&25\\82&-62&-18\end{array}\right)

Step-by-step explanation:

First multiply matrix A by -7.

Then multiply the matrix B by -6.

When multiplying a matrix by a number x you must multiply each element of the matrix by x.

<em><u>Then we perform operation -7A </u></em>

-7\left(\begin{array}{ccc}-10&10&8\\-2&-1&5\\-4&8&-6\end{array}\right)=\left(\begin{array}{ccc}70&-70&-56\\14&7&-35\\28&-56&42\end{array}\right)

<u><em>Now we perform operation -6B </em></u>

-6\left(\begin{array}{ccc}5&6&-4\\10&-6&-10\\-9&1&10\end{array}\right)=\left(\begin{array}{ccc}-30&-36&24\\-60&36&60\\54&-6&-60\end{array}\right)

Now we add the resulting matrices

\left(\begin{array}{ccc}70&-70&-56\\14&7&-35\\28&-56&42\end{array}\right)+\left(\begin{array}{ccc}-30&-36&24\\-60&36&60\\54&-6&-60\end{array}\right)=\left(\begin{array}{ccc}40&-106&-32\\-46&43&25\\82&-62&-18\end{array}\right)

7 0
3 years ago
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