Answer:
Alaina
Step-by-step explanation:
Although I might be wrong on this I dont think I am as it is the closest to -1 while being the farthest from -2
For there to be 1 car, we consider two possible outcomes:
The first door opened has a car or the second door opened has a car.
P(1 car) = 2/6 x 4/5 + 4/6 x 2/5
P(1 car) = 8/15
For there to be no car in either door
P(no car) = 4/6 x 3/5
P(no car) = 2/5
Probability of at least one car is the sum of the probability of one car and probability of two cars:
P(2 cars) = 2/6 x 1/5
= 1/15
P(1 car) + P(2 cars) = 8/15 + 1/15
= 3/5
Answer:
hmm
Step-by-step explanation:
Answer:
jbhbchbhvbbhcbrhfbcbhshshbhsvhbhv;b;rvbhbhcrbihcbhc
Step-by-step explanation:
Answer:
c= 1.16n
Step-by-step explanation:
j
