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2 years ago

What is the genotype and color of a homozygous recessive pumpkin if white is recessive to orange?

Biology

1 answer:

Anettt [7]2 years ago

5 0

gg is genotype and phenotype white

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The effect that yellowed or light-green leaves would have on a cucumber or tobacco plant

AURORKA [14]

Answer:

The effect would be that the green leaves, which contain chloroplasts, containing a chemical called chlorophyll would enable the plants to take in more energy in the form of sunlight, enabling the plants to photosynthesise and grow.

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3 years ago

Glycogen. starch, and cellulose are what

AnnyKZ [126]

Glycogen: Glycogen is the principal storage of Glucose.
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2 years ago

Which experment would most likely contain bias?

padilas [110]

Bias is defined as any tendency which prevents unprejudiced consideration of a question. In research, bias occurs when “systematic error [is] introduced into sampling or testing by selecting or encouraging one outcome or answer over others”.

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3 years ago

Which of the following statements is true for a eukaryotic cell?

xeze [42]

Possesses the characteristic of compartmentalization of organelles,wherein the organelles are bound by membranes

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2 years ago

In 1985 a biologist counted 750 pine trees in a 250 hectare forest. Using similar counting techniques, the biologist counted 1,2

Alisiya [41]

Answer:

Suppose that we have a given function f(x)

The average rate of change of the function between two values x₁ and x₂ is given by:

$r = \frac{f(x_2) - f(x_1)}{x_2 - x_1}$

a) We want to find the average (rate) of change on the size of population from 1985 to 1995.

We have that:

f(1985) = 750

f(1995) = 1500

Then we have:

$r = \frac{1500 - 750}{1995 - 1985} = 750/10 = 75$

This means that the population of trees increases, in average, at a rate of 75 trees per year.

b) What is the density of trees each year that they were counted?

This will be equal to the quotient between the number of trees and the area.

1985: number of trees = 750 pines

area = 250 ha

Then the density is:

D(1985) = (750 pines)/(250 ha) = 3 pines/ha

So 1985, there were 3 pines per hectare.

1990: number of trees = 1250 pines

area = 250 ha

Then the density is:

D(1990) = (1250 pines)/(250 ha) = 5 pines/ha

1995: number of trees = 1500 pines

area = 250 ha

The density is:

D(1995) = (1500 pines)/(250 ha) = 6 pines/ha

3) now we want to get the average change between 1985 and 1995 in the density, this will be:

$r = \frac{D(1995) - D(1885)}{1995 - 1985} = \frac{6 pines/ha - 3pines/ha}{10} = 0.3 pines/ha$

So, on average, each year the number of pines per hectare increases by 0.3

7 0

3 years ago