Write the first trigonometric function in terms of the second for θ in the given quadrant.. sec θ, sin θ; θ in quadrant I
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Answer:
Step-by-step explanation:
A line that passes through the point (4,-6) has a slope of 5/-4. Which of the following gives the equation of the line?
With the slope of 5/-4, and the ordered pair (4,-6) :
let m = 5/-4 (slope),
x1 = 4
y1 = -6
We can use those given values into the point-slope formula:
y - y1 = m(x - x1)
Plugging in those values will give you the answer:
y - (-6) = (x - 4)
Distribute into the terms inside the parenthesis:
y + 6 = + 5
Subtract 6 from both sides to isolate y:
y + 6 - 6 = +5 - 6
The equation of the line in slope-intercept form is: