1. H+S=40
2. 19H+25S=922
From 1,
19H+19S=760
Subtract this from 2 to eliminate H,
19H+25S-19H-19S=922-760
6S=162
Solve for S, then use either equation to solve for H.
Answer:
t=50 so C
Step-by-step explanation:
multiply both sides by 5
-t=-25-25
-t=-50
divide by -1
t=50
where u get t=50
<span>simplify third eqn -2x+5y+2x=4
5y=4
y=4/5
substitute back to 1st n 2nd eqn n solve for x n z
-4x-4-z=18 and -2x-4-2z=12
simplify -4x-z=22 and -2x-2z=16
-4x-(-x-8)=22
-3x+8=22
x=-14/3
z=-10/3
y=4/5
</span>
Answer:
<h2><u>
√
3</u></h2>
Step-by-step explanation:
Answer:
456.25m
Step-by-step explanation:
Since the question did not ask for what to find, we can as well look for the maximum height reached by the object
Given the height of an object thrown vertically expressed as;
s=-16t^2+100t+200.
At max height,
dS/dt = 0
-32t+100 = 0
-32t = -100
t = 100/32
t = 3.125s
Get the Max height
s(3.125) = -16(3.125)²+100(3.125)+200
s(3.125) = -156.25+312.5+200
s(3.125) = 456.25m
Hence the maximum height reached by the object is 456.25m
