Question

DO NOT COMMENT JUST FOR POINTS

Answer 1

Year Lawn Care Fee
2000 $750
2010 $1350

A. Initial value = $750 as it is given

Rate of change = (final value - initial value) / time = (1350 - 750)/10 = 600/10

= $60 per year


B. Let x be year in business since 2000, y be current yearly value

y = initial value + rate of change x year

y = 750 + 60x

Answer 2

Here, Series: 750, ............... 1350

It's an A.P. where, a = 750 a(11) = 1350

We know, a(n) = a + (n - 1)d
1350 = 750 + (11 - 1)d
1350 - 750 = 10d
600/10 = d
d = 60

In short, Rate of change would be; $60 per year.

B.) y-y1 = m(x - x1)
y - 750 = 60(x - 1)
y - 750 = 60x - 60
y = 60x + 690

In short, Your Equation would be: 60x + 690

Hope this helps!