Question

Which quadratic equation has the roots -1+4i and -1-4i

Answer 1

Answer:

C

Step-by-step explanation:

Solve the quadratic in answer choice C using the quadratic formula:

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}$.

Here a=1, b=2, and c=17.

Substitute and you'll have:

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{-2+/-\sqrt{(-2)^2-4(1)(17)} }{2(1)}=\frac{-2+/-\sqrt{4-68}}{2)}$

$\frac{-2+/-\sqrt{-64} }{2}=\frac{-2+/-8i }{2}=-1+/- 4i$