Answer:
14 = x and 2.5 = y
Step-by-step explanation:
For ABCD - the top is 8 and the sides are 11. 11 minus 8 is 3. 11 plus 3 equals 14, that’s x.
For GHIJ - the bottom is 8 and both sides are 5.5. So 8 minus 5.5 is 2.5. That’s y.
To solve this problem, let us first assign some
variables. Let us say that:
x = pigs
y = chickens
z = ducks
From the problem statement, we can formulate the
following equations:
1. y + z = 30 --->
only chicken and ducks have feathers
2. 4 x + 2 y + 2 z = 120 --->
pig has 4 feet, while chicken and duck has 2 each
3. 2 x + 2 y + 2 z = 90 --->
each animal has 2 eyes only
Rewriting equation 1 in terms of y:
y = 30 – z
Plugging this in equation 2:
4 x + 2 (30 – z) + 2 z = 120
4 x + 60 – 2z + 2z = 120
4 x = 120 – 60
4 x = 60
x = 15
From the given choices, only one choice has 15 pigs. Therefore
the answers are:
She has 15 pigs, 12 chickens, and 18 ducks.
Answer:
$576.80
Step-by-step explanation:
We have been given that Mr. Juárez opened a savings account with an initial deposit of $560 and will not make any additional deposits or withdrawals. The account earns 1% simple interest.
We are asked to find the total amount that Mr. Juárez will have in his account at the end of 3 years.
We will use simple interest formula to solve our given problem.
A = Final amount after t years,
P = Principal amount,
r = Annual interest rate in decimal form,
t = Time in years.
Let us convert 1% into decimal form,
1%=1/100=0.01
P=$560 and t=3
A=$560 (1+0.01(3))
A=$560 (1+0.03)
A= $560 (1.03)
A= $576.80
Therefore, Mr. Juárez will have $576. 80 in his account at the end of 3 years. Hope this helps!
Answer: he invested $15000 in part 1 and $60000 in part 2
Step-by-step explanation:
Let x represent the amount of money invested in part one.
Let 4x represent the amount of money invested in part 2 .
Total amount of money invested in part 1 and part 2 is
x + 4x = 5x
The formula for simple interest is expressed as
I = PRT/100
Where
P is the principal or initial amount.
T is the duration in years
R is the number rate.
For part 1
R = 7%
T = 1 year
P = x
I = (x × 7 × 1)/100 = 0.07x
For part 2,
R = 11%
T = 1 year
P = 4x
I = (4x × 11 × 1)/100 = 0.44x
if the total annual income from interest is 7650. This means that
0.44x + 0.07x = 7650 - - - - - - - -2
0.51x = 7650
x = 7650/0.51
x = 15000
Amount invested in part 1 is $15000
Amount invested in part 2 is 4×15000 = $60000
