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telo118 [61]
3 years ago
6

How many time larger is 5000 to 5

Mathematics
2 answers:
tekilochka [14]3 years ago
6 0

Answer:

1000 ( divide 5000 by 5 )

disa [49]3 years ago
3 0

Answer:

1000 times larger.

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=f%28x%29%3D16t%5E2%2B32t" id="TexFormula1" title="f(x)=16t^2+32t" alt="f(x)=16t^2+32t" align="
Nataly_w [17]

Answer:

- time = 1second

- maximum height = 16m

Step-by-step explanation:

Given the height of a pumpkin t seconds after it is launched from a catapult modelled by the equation

f(t)=-16t²+32t... (1)

The pumpkin reaches its maximum height when the velocity is zero.

Velocity = {d(f(x)}/dt = -32t+32

Since v = 0m/s (at maximum height)

-32t+32 = 0

-32t = -32

t = -32/-32

t = 1sec

The pumpkin reaches its maximum height after 1second.

Maximum height of the pumpkin is gotten by substituting t = 1sec into equation (1)

f(1) = -16(1)²+32(1)

f(1) = -16+32

f(1) = 16m

The maximum height of the pumpkin is 16m

6 0
3 years ago
Victoria is going to a carnival that has games and rides. Each game costs $2 and each ride costs $4. Victoria spent $16 altogeth
TiliK225 [7]

Answer:

2 rides & 4 games

Step-by-step explanation:

2 rides=$8

4 games=$8

8+8=$16

8 0
3 years ago
a group of fitness club members lose a combined total of 28 kilograms in 1 week. there are approximately 2.2 pounds in 1 kilogra
olga55 [171]
The group lose 8.8 pounds per day. For a detailed calculation, please refer to the attachment.
Download docx
6 0
3 years ago
Manuel is putting money into a savings account. He starts with
olga55 [171]
S=350 your starting amount + 30w which is 30× the number of weeks (19) which comes out to give you s=920 if I did it correctly
4 0
3 years ago
A customer service phone line claims that the wait times before a call is answered by a service representative is less than 3.3
Vika [28.1K]

Answer:

(A) Yes, since the test statistic is in the rejection region defined by the critical value, reject the null. The claim is the alternative, so the claim is supported.

Step-by-step explanation:

Null hypothesis: The wait time before a call is answered by a service representative is 3.3 minutes.

Alternate hypothesis: The wait time before a call is answered by a service representative is less than 3.3 minutes.

Test statistic (t) = (sample mean - population mean) ÷ sd/√n

sample mean = 3.24 minutes

population mean = 3.3 minutes

sd = 0.4 minutes

n = 62

degree of freedom = n - 1 = 62 - 1 = 71

significance level = 0.08

t = (3.24 - 3.3) ÷ 0.4/√62 = -0.06 ÷ 005 = -1.2

The test is a one-tailed test. The critical value corresponding to 61 degrees of freedom and 0.08 significance level is 1.654

Conclusion:

Reject the null hypothesis because the test statistic -1.2 is in the rejection region of the critical value 1.654. The claim is contained in the alternative hypothesis, so it is supported.

5 0
3 years ago
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