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tiny-mole [99]
4 years ago
12

The coordinates of point P on a coordinate grid are (−5, −6). Point P is reflected across the y-axis to obtain point Q and acros

s the x-axis to obtain point R. What are the coordinates of points Q and R?
1. Q(5, 6) and R(−5, −6)

2. Q(−5, −6) and R(5, 6)

3. Q(−5, 6) and R(5, −6)

4. Q(5, −6) and R(−5, 6)
Mathematics
2 answers:
Natali [406]4 years ago
7 0
Q(−5, 6) and R(5, −6) hope I helped you :)
Llana [10]4 years ago
4 0
Hey friend!
Let's figure this out!

P(−5, −6)
reflect about y axis
Q(5, -6)
reflect about x axis
R(5,6)


So that gives you the answer!
3. Q(−5, 6) and R(5, −6)



Hope this helped!
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Another one lol(picture)
Andreyy89
Look up the law of sines, I suggest Khan Academy. It is better if you know how to do it, it is very useful.
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3 years ago
MCR3U1 Culminating 2021.pdf
11111nata11111 [884]

Answer:

(a) y = 350,000 \times (1 + 0.07132)^t

(b) (i) The population after 8 hours is 607,325

(ii) The population after 24 hours is 1,828,643

(c) The rate of increase of the population as a percentage per hour is 7.132%

(d) The doubling time of the population is approximately, 10.06 hours

Step-by-step explanation:

(a) The initial population of the bacteria, y₁ = a = 350,000

The time the colony grows, t = 12 hours

The final population of bacteria in the colony, y₂ = 800,000

The exponential growth model, can be written as follows;

y = a \cdot (1 + r)^t

Plugging in the values, we get;

800,000 = 350,000 \times (1 + r)^{12}

Therefore;

(1 + r)¹² = 800,000/350,000 = 16/7

12·㏑(1 + r) = ㏑(16/7)

㏑(1 + r) = (㏑(16/7))/12

r = e^((㏑(16/7))/12) - 1 ≈ 0.07132

The  model is therefore;

y = 350,000 \times (1 + 0.07132)^t

(b) (i) The population after 8 hours is given as follows;

y = 350,000 × (1 + 0.07132)⁸ ≈ 607,325.82

By rounding down, we have;

The population after 8 hours, y = 607,325

(ii) The population after 24 hours is given as follows;

y = 350,000 × (1 + 0.07132)²⁴ ≈ 1,828,643.92571

By rounding down, we have;

The population after 24 hours, y = 1,828,643

(c) The rate of increase of the population as a percentage per hour =  r × 100

∴   The rate of increase of the population as a percentage = 0.07132 × 100 = 7.132%

(d) The doubling time of the population is the time it takes the population to double, which is given as follows;

Initial population = y

Final population = 2·y

The doubling time of the population is therefore;

2 \cdot y = y \times (1 + 0.07132)^t

Therefore, we have;

2·y/y =2 = (1 + 0.07132)^t

t = ln2/(ln(1 + 0.07132)) ≈ 10.06

The doubling time of the population is approximately, 10.06 hours.

8 0
3 years ago
I don't know how to answer this question.
laiz [17]

Answer:

- 39/8y

Step-by-step explanation:

First you need to find a common denominator:

There is already a y in both denominators, so you don't have to worry about that. Since only one denominator has an 8, the other needs to have an 8, so you need to multiply the first fraction by 8 → - 4/y * 8 = - 32/8y

From here you can subtract the numerators:

- 32/8y +(- 7/8y) = - 39/8y

Because you are adding a negative to a negative, it makes the number mroe negative


I hope this helps!

3 0
3 years ago
HELP HELP HELP<br> HELP HELP <br> HELP <br> (STEP BY STEP)
Marizza181 [45]

With some simple rearrangement, we can rewrite the numerator as

2x^3 - 3x^2 - x + 4 = 2(x^3 - x) - 3x^2 + x + 4 \\\\ ~~~~~~~~ = 2x(x^2-1) - 3(x^2 - 1) + x + 1 \\\\ ~~~~~~~~ = (2x-3)(x^2-1) + x+1

Then factorizing the difference of squares, x^2-1=(x-1)(x+1), we end up with

\dfrac{2x^3 - 3x^2 - x + 4}{x^2 - 1} = \dfrac{(2x-3)(x-1)(x+1) + x+1}{(x-1)(x+1)} \\\\ ~~~~~~~~ = \boxed{2x-3 + \dfrac1{x-1}}

3 0
2 years ago
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