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rusak2 [61]
3 years ago
14

Given that the first term and the common difference of an arithmetic progression are 6 and 3 respectively. Calculate the sum of

all terms from 4th term to the 14th term.​
Mathematics
1 answer:
Goryan [66]3 years ago
5 0

Answer:

330

Step-by-step explanation:

Evaluate the sum of 14 terms and subtract the sum of the first 3 terms

The sum to n terms of an arithmetic sequence is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ], so

S_{14} = 7 [ (2 × 6) + (13 × 3)]

                         = 7(12 + 39) = 7 × 51 = 357

S_{3} = 6 + 9 + 12 = 27

Sum of terms from 4 th to 14 th = 357 - 27 = 330

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