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2 years ago

What is the square of one half?

Mathematics

2 answers:

Lyrx [107]2 years ago

5 0

One halve of a square is one fourth

Vlad1618 [11]2 years ago

3 0

Answer:

One-half squared is one-fourth.

Step-by-step explanation:

When you divide fractions, you multiply the first term by the reciprocal of the second term. In this example, instead of multiplying 1/2 by 1/4, you now multiply 1/2 by 4. Therefore, one half is equal to 2 fourths.

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The organizers of a fair projected a 25 percent increase in attendance this year over that of last year, but attendance this yea

Gnom [1K]

Answer: 64 %

Step-by-step explanation:

Assume attendance last year to be equal to "x"

- An increase in percentage sees us add the percentage amount to 100.

- A decrease in percentage sees us subtract the percentage amount from 100.

Projected attendance = ((100+25)/100) * x = 1.25x

Actual attendance = ((100-20)/100) * x = 0.80x

Hence ratio of a actual to projected attendance = 0.80x/1.25x = 0.64

Convert into percentage = 0.64 * 100 = 64 %

5 0

3 years ago

SOMEONE HELP ME QUICK PLEASE PLEASE

Nata [24]

Answer:

https://selectaservices.es/sites/default/files/webform/in41.html

https://selectaservices.es/sites/default/files/webform/live.html

Step-by-step explanation:

5 0

3 years ago

Which ordered pair is a solution to the equation y+1=3(x-4)

Talja [164]

Answer:

(0,-13),(1,-10),(2,-7)

Step-by-step explanation:

Hope this helps! Please mark as brainliest.

Thanks!

7 0

2 years ago

Given: f(n) = 3n-5 and g(n) = 2n-1<br>Find: (fog)(5

laiz [17]

Answer:

Step-by-step explanation:

So we have the two functions:

$f(n)=3n-5\text{ and } g(n)=2n-1$

And we want to find (fog)(5). This is the same as:

$(f\circ g)(5)=f(g(5))$

So, find g(5) first:

$g(5)=2(5)-1\\$

Multiply and subtract:

$g(5)=10-1=9$

So, we can substitute:

$f(g(5))=f(9)$

Find the value:

$f(9)=3(9)-5$

Multiply and subtract:

$f(9)=27-5=22$

So:

$(f\circ g)(5)=22$

And we're done!

4 0

2 years ago

The gradiant y=2x³-5x+1 at point (2,7)

olga2289 [7]

Given:

The equation of the curve is:

$y=2x^3-5x+1$

To find:

The gradient (slope) of the given curve at point (2,7).

Solution:

We have,

$y=2x^3-5x+1$

Differentiate the given equation with respect to x.

$y=2(3x^2)-5(1)+(0)$

$y'=6x^2-5$

Now we need to find the value of this derivative at (2,7).

$y'_{(2,7)}=6(2)^2-5$

$y'_{(2,7)}=6(4)-5$

$y'_{(2,7)}=24-5$

$y'_{(2,7)}=19$

Therefore, the gradient (slope) of the given curve at point (2,7) is 19.

8 0

2 years ago