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Vedmedyk [2.9K]
3 years ago
10

What is the square of one half?

Mathematics
2 answers:
Lyrx [107]3 years ago
5 0
One halve of a square is one fourth
Vlad1618 [11]3 years ago
3 0

Answer:

One-half squared is one-fourth.

Step-by-step explanation:

When you divide fractions, you multiply the first term by the reciprocal of the second term. In this example, instead of multiplying 1/2 by 1/4, you now multiply 1/2 by 4. Therefore, one half is equal to 2 fourths.

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Directions: Evaluate the following combinations and determine the value of the
Andru [333]

Answer:

1. C(9,4) : n=9, s=4

2. C(10,5) : r=5

3. C(5,5) : n=5

4. C(7,7) : n=6

5. C(18,17) : r=3

Step-by-step explanation:

4 0
3 years ago
Sponge Bob took 30 minutes to walk a mile last week.
sergey [27]
-20%
work:
(24-30):30*100=
(24:30-1)*100=
80-100=-20
6 0
3 years ago
Whole-wheat bread costs $2.06/lb. How much would 3.8 lb of whole-wheat bread cost?
Xelga [282]
Whole-wheat bread = $2.06/lb

We need the cost of 3.8 lbs of whole-wheat bread.

So, we simply need to multiply the cost with the amount needed.

(cost per pound) × (amount of bread)

($2.06) × (3.8)

Simplify.

$7.828

Round to the nearest tenths.

$7.83

So, 3.8 pounds of whole wheat bread costs $7.83

~Hope I helped!~


7 0
3 years ago
Read 2 more answers
You need to count all the loaves of bread in the front area. There are 22 loaves of white bread , 17 loaves of wheat bread , and
pickupchik [31]
This is easy first do 22+17=39
next do 39+19=58
3 0
3 years ago
Read 2 more answers
The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth
Art [367]

Answer:

a) N_0=250\; k=0.15

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies t=0. And N(0)=N_0. The process is:

N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250

b) After 2 days means t=48. So, we just replace and operate:

N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}

c) N(t_1)=4000; \;t_1=?

N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\  \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h

d) t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)

N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h

6 0
3 years ago
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