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3 years ago

What is the square of one half?

Mathematics

2 answers:

Lyrx [107]3 years ago

5 0

One halve of a square is one fourth

Vlad1618 [11]3 years ago

3 0

Answer:

One-half squared is one-fourth.

Step-by-step explanation:

When you divide fractions, you multiply the first term by the reciprocal of the second term. In this example, instead of multiplying 1/2 by 1/4, you now multiply 1/2 by 4. Therefore, one half is equal to 2 fourths.

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Pete has 3 dollars less than what Linda has. If together has 81 dollars how much does each person have?

Makovka662 [10]

Answer:

Pete: 39, Linda: 42

Step-by-step explanation:

Suppose Pete has x dollars. If he has 3 dollars less than Linda, then Linda has 3+x dollars. Together, they have 81 dollars:

x+3+x=81

2x+3=81

2x=78

x=39

Since Pete has x dollars, and x=39, he has $39.

Linda has 3+x, which is 39+3 = $42

I hope this helps! :)

8 0

3 years ago

Divide £30 between 2 people in the ratio 1:2

yuradex [85]

1+2=3.
30/3=10
10x1=10
10x2=20
So the answer would be £10:£20
And to check if it’s right £10 + £20= £30

3 0

4 years ago

Read 2 more answers

All I need is for someone to explain how you get this answer !!

ale4655 [162]

This is one of the easiest ways to get the answer

4 0

3 years ago

Read 2 more answers

9(-6X-2) -7 (-10X-2)

Maksim231197 [3]

9(-6x-2)-7(-10x-2)
Simplify, by distributing the 9 and the -7
-54x-18+70x+14
Combine like terms
16x-4 is the simplified expression

Hope this helped!

3 0

3 years ago

Dwayne drove 18 miles to the airport to pick up his father and then returned home. On the return trip he was able to drive an av

Nesterboy [21]

Answer:

30 mph

Step-by-step explanation:

Let d = distance (in miles)

Let t = time (in hours)

Let v = average speed driving to the airport (in mph)

⇒ v + 15 = average speed driving from the airport (in mph)

Using: distance = speed x time

$\implies t=\dfrac{d}{v}$

Create two equations for the journey to and from the airport, given that the distance one way is 18 miles:

$\implies t=\dfrac{18}{v} \ \ \textsf{and} \ \ t=\dfrac{18}{v+15}$

We are told that the total driving time is 1 hour, so the sum of these expressions equals 1 hour:

$\implies \dfrac{18}{v} +\dfrac{18}{v+15}=1$

Now all we have to do is solve the equation for v:

$\implies \dfrac{18(v+15)}{v(v+15)} +\dfrac{18v}{v(v+15)}=1$

$\implies \dfrac{18(v+15)+18v}{v(v+15)}=1$

$\implies 18(v+15)+18v=v(v+15)$

$\implies 18v+270+18v=v^2+15v$

$\implies v^2-21v-270=0$

$\implies (v-30)(v+9)=0$

$\implies v=30, v=-9$

As v is positive, v = 30 only

So the average speed driving to the airport was 30 mph

(and the average speed driving from the airport was 45 mph)

8 0

2 years ago

Read 2 more answers