At what temperature did the gas have a volume of 110 mL?<br> 300 K<br> 110 K<br> 20 K<br> 19 K

Write an algebraic expression for the phrase. the sum of f and 6 f – 6 f + 6 6f

konstantin123 [22]

The sum means adding, so your answer is f + 6

6 0

3 years ago

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Find the measure of <C in the following figure:

Yuki888 [10]

Answer:

angle C =160 degree

Step-by-step explanation:

since the given triangle is an isosceles triangle their base angles must be equal. So,

x - 10 =x/2

2(x - 10) =x

2x - 20 = x

2x - x = 20

x = 20

for angle B

x - 10

20 - 10

10 degree

for angle A

x/2

20/2

10

For angle c

angle A + angle B + angle C =180 degree (sum of interior angle of a triangle)

10 + 10 + angle C =180

20 + angle C =180

angle C =180 - 20

angle C =160 degree

5 0

3 years ago

Suppose that the population of the scores of all high school seniors who took the SAT Math (SAT-M) test this year follows a Norm

Vlad1618 [11]

Answer:

Confidence = $1-\alpha=1-0.01=0.99$

And then the confidence level would be given by 99%

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma)$

The distribution for the sample mean is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\bar x =512$ represent the sample mean

$\sigma=100$ represent the population standard deviation

n= 100 sample size selected.

The confidence interval is given by this formula:

$\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$ (1)

The marginof error for this case is given by Me=25.76. And we know that the formula for the margin of error is given by:

$Me=z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

$25.76=z_{\alpha/2} \frac{100}{\sqrt{100}}$

And we can find the critical value $z_{\alpha/2}$ like this:

$z_{\alpha/2}=\frac{25.76(\sqrt{100})}{100}=2.576$

And we know that on the right tail of the z score =2.576 we have $\alpha/2$ of the total area. We can find the area on the right of the z score using this excel code:

"=1-NORM.DIST(2.576,0,1,TRUE)" or using a table of the normal standard distribution, and we got 0.004998= $\alpha/2$ , so then $\alpha=0.00498*2=0.009995 \approx 0.01$ , and then we can find the confidence like this: