Answer:
Given: △ABC, m∠B=90° AB=12, BC=16, BK ⊥ AC . Find: AC and BK.
Given: △ABC, m∠B=90°
Find: AC and BK.
Short leg 90 degrees Long leg Hypotenuse
AB=12 90 BC=16 AC= ?
AK = ? 90 BK = ? AB=12
AC = SQRT (AB*AB + BC*BC) = 20 [right triangle; Pythagorean Theorem]
Similar triangles:[Note: In diagram, share two angles. Therefore share three angles]
BK / 16 = AB / AC
BK / 16 = 12 / 20
BK = (3/5)16
BK = 48/5
another answer let see this
AB^2+BC^2=AC^2
12^2+16^2=AC^2
144+256=AC^2
400=AC^2
20=AC
# be careful#
Answer:
Step-by-step explanation:
(3-7)/(-2+1)= -4/-1= 4
y - 7 = 4(x + 1)
y - 7 = 4x + 4
y = 4x + 11
The top question is B. 30, because you have to set 7y-30 equal to 4y+60 since both lengths are the same.
Yes because all equilateral triangles have equal angles and side lengths so they are all similar. hope i helped -J
Answer:
<em>1.3%</em>
When entered into a calculator, 12/890 (the chance of a given calculator being defective) = 0.01348...
As a percent this is 100*0.01348% = 1.348%, and to the nearest tenth, 1.3%
