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pshichka [43]
3 years ago
14

Find the measure of an interior angle and an exterior angle of a regular octagon

Mathematics
1 answer:
garik1379 [7]3 years ago
7 0
Since the pentagon is a regular<span> pentagon, the </span>measure<span> of each </span>interior angle<span> will be the same. To </span>find<span> the size of each </span>angle<span>, divide the sum, 540º, by the number of </span>angles in<span> the pentagon. (which is the same as the number of sides). There are 108° in each </span>interior angle of a regular<span> pentagon.</span>
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Number 18 pls help me
Harman [31]
Lila did it correctly. The answer is 324

Following PEMDAS, we first focus on the parenthesis. So we simplify 9-3 to get 6

So we go from 
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The next step is applying exponents. In this case, squaring the terms, so we go from
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Next is multiplying
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Finally, add up 288 and 36 to get 288+36 = 324

That confirms that Lila is correct

----------------------

The error that Rob made is that he computed 18*4^2+9^2-3^2 but it is NOT correct. Saying (x-y)^2 = x^2-y^2 isn't a true equation for all x and y. Again you have to simplify what is in the parenthesis first, and then you can square it. Or you must use the FOIL rule to expand out (9-3)^2


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