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yaroslaw [1]
3 years ago
6

What the answer now

Mathematics
1 answer:
stiks02 [169]3 years ago
7 0

Answer:

35.6 yd²

Step-by-step explanation:

Area of ∆UVW can be solved if we know the lengths of 2 sides and their included angle.

We are Given just 1 side, UV (w). Use the law of sines to find UW (v).

Thus:

\frac{v}{sin(V)} = \frac{w}{sin(W)}

W = 137°

w = 19 yd

V = 180 - (137 + 22) = 21°  => sum of triangle

v = ??

Plug in the values and solve for v

\frac{v}{sin(21)} = \frac{19}{sin(137)}

Multiply both sides by sin(21)

\frac{v}{sin(21)}*sin(21) = \frac{19}{sin(137)}*sin(21)

v = \frac{19*sin(21)}{sin(137)}

v = 10 yd (approximated)

Find area of ∆UVW:

Area = ½*UV*UW*sin(U)

Area = ½*v*w*sin(U)

= ½*10*19*sin(22)

Area = 35.6 yd² (to nearest tenth)

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Now decompose the remainder term into partial fractions:

(4<em>x</em>² - 15<em>x</em> - 4) / ((<em>x</em>² + 4) (<em>x</em> - 3)) = (<em>ax</em> + <em>b</em>) / (<em>x</em>² + 4) + <em>c</em> / (<em>x</em> - 3)

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Then

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and so

(3<em>x</em>³ - 5<em>x</em>² - 3<em>x</em> - 40) / ((<em>x</em>² + 4) (<em>x</em> - 3))

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The given equation is the best line that approximates the linear

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