All categories

3 years ago

If ΔABC is reflected across the y-axis, what are the resulting coordinates for points A', B', and C'

Mathematics

1 answer:

Sever21 [200]3 years ago

4 0

Answer:

Step-by-step explanation:

Reflection across the y axis changes the x value.

Reflection across the x axis changes the y value.

This is counterintuitive, but it is correct.

(-1,6)

(-2,1)

(-5,2)

Do you see what happened. All the values for x become - values because you are moving an equal distance in the -x direction

You might be interested in

Finding Derivatives Implicity In Exercise,Find dy/dx implicity.<br> x2e - x + 2y2 - xy = 0

Klio2033 [76]

Answer:

the question is incomplete, the complete question is

"Finding Derivatives Implicity In Exercise,Find dy/dx implicity . $x^{2}e^{-x}+2y^{2}-xy$ "

Answer : $\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}$

Step-by-step explanation:

From the expression $x^{2}e^{-x}+2y^{2}-xy$ " y is define as an implicit function of x, hence we differentiate each term of the equation with respect to x.

we arrive at

$\frac{d}{dx}(x^{2}e^{-x )+\frac{d}{dx} (2y^{2})-\frac{d}{dx}xy=0\\$

for the expression $\frac{d}{dx}(x^{2}e^{-x})$ we differentiate using the product rule, also since y^2 is a function of y which itself is a function of x, we have

$(2xe^{-x}-x^{2}e^{-x})+4y\frac{dy}{dx}-x\frac{dy}{dx} -y=0\\\\(2-x)xe^{-x}+(4y-x)\frac{dy}{dx}-y=0 \\$ .

if we make dy/dx subject of formula we arrive at

$(4y-x)\frac{dy}{dx}=y-(2-x)xe^{-x}\\\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}$

5 0

3 years ago

one x-intercept for a parabola is at the point (2, 0). use the quadratic formula to find the other x-intercept for the parabola

omeli [17]

Answer:

Step-by-step explanation:

There are 3 ways to find the other x intercept.

1) Polynomial Long Division.

Divide x^2 - 3x + 2 by the binomial x - 2, because by the Factor Theorem if a is a root of a polynomial then x - a is a factor of said polynomial.

2) Just solving for x when y = 0, by using the quadratic formula.

$x^2 - 3x + 2 = 0\\x_{12} = \frac{3 \pm \sqrt{9 - 4(1)(2)}}{2} = \frac{3 \pm 1}{2} = 2, 1$ .

So the other x - intercept is at (1, 0)

3) Using Vietta's Theorem regarding the solutions of a quadratic

Namely, the sum of the solutions of a quadratic equation is equal to the quotient between the negative coefficient of the linear term divided by the coefficient of the quadratic term.

$x_1 + x_2 = \frac{-b}{a}$

And the product between the solutions of a quadratic equation is just the quotient between the constant term and the coefficient of the quadratic term.

$x_1 \cdot x_2 = \frac{c}{a}$

These relations between the solutions give us a brief idea of what the solutions should be like.

6 0

3 years ago

Bryan paid $136.00 for an item at the store that was 20% off the original price. What was the original price?

Dennis_Churaev [7]

The original price was $270.00

4 0

2 years ago

Sabina makes $2,000 per month. She spends $150 on store credit and $250 on an auto loan each month. Does she have excessive debt

never [62]

Answer:

The answer is B because her debt to income ratio is lower than 36 percent

7 0

3 years ago

What is the value of fraction 1 over 2x3 + 5.3y, when x = 2 and y = 3?

NikAS [45]

Hello, let's figure this one out together.

Me, myself had to write this down in the notes form to understand what I was doing.

In the fraction, multiply the 2's by 3.

1 over 2(2^3)+5.3(3)

1 over 2(2^3)+(5.3)(3)

Simplify each by step.

You end of up with a decimal.

You have a total of 0.031348.

4 0

3 years ago