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Ksju [112]
3 years ago
15

Natalie just rented an apartment for $900 a month. She was told the rent will increase 5.5 %each year. About how much will her r

ent be in 7 years?
Mathematics
2 answers:
zlopas [31]3 years ago
7 0

The rent of the apartment per month = $900.

Each year the rent will increase at a rate of 5.5%.

We have to find what will be the rent after 7 years. To find that we will use compound interest formula here.

The formula is A = P(1+r)^t

Where, A is the last amount including interest, P = principal amount, r = rate of interest, t = number of years.

Here, P = $900, r = 5.5% = \frac{5.5}{100}= 0.055, t = 7

By substituting the values in the formula we will get,

A = 900(1+0.055)^7

A = 900(1.055)^7

A = 1309.2 (Approximately taken upto nearest tenth)

We have got the required answer.

After 7 years the rent will be $1309.2.

torisob [31]3 years ago
6 0
Each year the rent is multiplied by (1+0.055), so in 7 years, Natalie's rent will be
.. $900*1.055^7 = $1309.21
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750 divided by 3=250 just add your point were before five and 7.50 plus 7.50 equals 15 plus 7.50 equals 22.50

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What is 4 yards and 2 feet multiplied by 3
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12 yds and 6 feet, aka 42 feet.

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8 0
3 years ago
D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x
MA_775_DIABLO [31]
The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

and has characteristic equation

r^2-16k=0\implies r=\pm4\sqrt k

which admits the characteristic solution y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}.

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

So you have

16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x

This means

16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}
b(1-16k)=30\implies b=\dfrac{30}{1-16k}

and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
8 0
3 years ago
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