Answer:
52/27
Step-by-step explanation:
Answer:
The dimension of the play area written algebraically is y²/2 + 9y
Step-by-step explanation:
Let the be x and the width be y
If the length is to be 9 feet longer than half the width,
hence y/2 + 9 = x
hence dimension of the area = (y/2 + 9) × y = y²/2 + 9y
The function would be:
6.95 + (0.75*t) = p
The answer is 1/2 the last one
Answer:
Step-by-step explanation:
if these are diagonals ,then
area=(product of diagonals)/2
=(6*14)/2=42 ft²
