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4 years ago

9

I need help plz help me I need your help plz help me I’m begging you I need your help it’s an emergency I’m begging you plz help

me

2 answers:

Katena32 [7]4 years ago

8 0

6x5=30

6x12=72

Add the variable.

30x-72

kari74 [83]4 years ago

5 0

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Multiply each term in the parenthesis by 6

6 x 5z = 30z

6 x - 12 = -72

It would be 30z - 72

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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Which quadratic equation has solutions x=8 and x=−1?

andrezito [222]

There are two ways you can do this

$Using the formula$

${x}^{2} - (sum \: of \: roots)x + poduct \: of \: roots = 0$

${x}^{2} - (8+-1)x + - 1 \times 8 = 0$

${x}^{2} - 7x - 8 = 0$

$Working backwards$

$x = 8 \: or \: x = - 1$
$\Rightarrow x-8=0 \: or \: x+1=0$

$\Rightarrow (x-8)(x + 1)=0$
$\Rightarrow {x}^{2} + x -8x - 8 = 0$
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4 years ago

Which two ratios represent quantities that are proportional?

vesna_86 [32]

Answer:

B

Step-by-step explanation:

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3 years ago

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LuckyWell [14K]

Answer:

it's the bottom left one

Step-by-step explanation:

Im just a kid, don't ask

So -1/4x+1/2 x would be 1/4 x because -0.25+0.5=0.25

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:) Im an idiot lol

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2 years ago

Read 2 more answers

PLS HELP! NO GUESSING<br><br> 5r + r3s<br><br> IS IT A MONOMIAL YES OR NO EXPLAIN ANSWER

Natalka [10]

Nope, <span>5r + r3s is not a monomial.
Monomials cannot include addition or subtraction, and since this uses addition, it is not a monomial.
</span>

I hope this helps and have a great day! If you need anymore help you can link me to another question and I will try to solve it!

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3 years ago

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How do you solve 9| x+8 | + 10 < 55 & how is it graphed

mafiozo [28]

Hello!

First, let's write the problem.
$9\left|x+8\right|+10\ \textless \ 55|x+8|+10\ \textless \ 55$
Subtract 10 from both sides.
$9\left|x+8\right|+10-10\ \textless \ 55-10$
$9\left|x+8\right|\ \textless \ 45$
Divide both sides by 9.
$\frac{9\left|x+8\right|}{9}\ \textless \ \frac{45}{9}$
$\left|x+8\right|\ \textless \ 5$
When we got absolute value, we are going to get two results.
$x+8\ \textless \ 5$
and
$x+8\ \textgreater \ -5$

Let's solve the first one,
$x+8\ \textless \ 5x+8\ \textless \ 5$
Subtract 8 from both sides.
$x+8-8\ \textless \ 5-8$
$x\ \textless \ -3x\ \textless \ -3$

Let's solve the second one.
$x+8\ \textgreater \ -5$
Subtract 8 from both sides.
$x+8-8\ \textgreater \ -5-8$
$x\ \textgreater \ -13x\ \textgreater \ -13$

Let's combine the ranges.
$-13\ \textless \ x\ \textless \ -3$

The attachment shows how would you graph it.
You can feel free to let me know if you have any questions regarding this.
Thanks!

- TetraFish

3 0

3 years ago