Answer:
Doesn't have solution.
Step-by-step explanation:
x ≠ 0; x > 0 (I)
x - 5 > 0
x > 5 (II)
![log_6 x + log_6 (x + 5) = 2 \\\ log_6 [x(x + 5)] = 2 \\\ x^2 + 5x = 36 \\\ x^2 + 5x - 36 = 0 \\\ \Delta = 5^2 - 4.1.(- 36) \\\ \Delta = 169 \\\ \sqrt{\Delta} = \pm 13 \\\ x' = \frac{- 5 + 13}{2} \\\\ x' = 4 \\\ x" = \frac{- 5 - 13}{2} \\\\ x" = - 9](https://tex.z-dn.net/?f=log_6%20x%20%2B%20log_6%20%28x%20%2B%205%29%20%3D%202%20%5C%5C%5C%20log_6%20%5Bx%28x%20%2B%205%29%5D%20%3D%202%20%5C%5C%5C%20x%5E2%20%2B%205x%20%3D%2036%20%5C%5C%5C%20x%5E2%20%2B%205x%20-%2036%20%3D%200%20%5C%5C%5C%20%5CDelta%20%3D%205%5E2%20-%204.1.%28-%2036%29%20%5C%5C%5C%20%5CDelta%20%3D%20169%20%5C%5C%5C%20%5Csqrt%7B%5CDelta%7D%20%3D%20%5Cpm%2013%20%5C%5C%5C%20x%27%20%3D%20%5Cfrac%7B-%205%20%2B%2013%7D%7B2%7D%20%5C%5C%5C%5C%20x%27%20%3D%204%20%5C%5C%5C%20x%22%20%3D%20%5Cfrac%7B-%205%20-%2013%7D%7B2%7D%20%5C%5C%5C%5C%20x%22%20%3D%20-%209)
Then, this expression doesn't have solution.
I Hope I've helped you.
This will be solved by solving for x first. Firstly you multiply the top equation by 2 and the bottom by -3. This will change both equation to (top)-10x+6y=-54 and (bottom) 27x-6y=-57. Now when you add the factors the y-values cancel out leaving you with; 17x=-3. now you have to divide by 17 on both sides giving you x=-0.17647058823 (not the prettiest solution but you can round if you want to). After that pick an equation to solve for y (I'm picking the top); the equation will be 5(-0.17647058823)+3y=-27. multiply the negative decimal and 5 to get -0.88235294117 (again not the prettiest). Add that to both sides which will give you 3y=-26.1176470588. After this divide both sides by 3 which will give you y=-8.70588235294. Your answer is (-0.17647058823,-8.70588235294) You can divide to the second or third decimal if needed-----remember that as you round from left to right on a decimal if it's below five you leave it and if it's above 5 then round up 1. I hope this help :)
Answer:
y=2/-1 -3
Step-by-step explanation:
This is a relatively simple half life calculation.
To go from 6 to 3 grams, 1622 years is required.
3 to 1.5 grams another 1622 years is required.
So, it undergoes exactly 2 half-lives or 3,244 years.
To see more about half-life click here:
http://www.1728.org/halflife.htm
Answer:
D
Step-by-step explanation:
side HG is 3
side FG is 5 hypotenuse
sin F = 3/5 = opposite/hypotenuse
cos G is adjacent/hypotenuse
adjacent side is HG which = 3
hypotenuse is 5
