Answer:
The 98% confidence interval for the mean amount of money spent on lunch per week for all students is between $13.3 and $16.7.
Step-by-step explanation:
A confidence interval has the following format.
In which is the mean of the sample and M is the margin of error.
In this problem, we have that:
The 98% confidence interval for the mean amount of money spent on lunch per week for all students is between $13.3 and $16.7.
Answer:
(15 – 22x)/4x(2x – 5)
Step-by-step explanation:
Let us take the numerator first:
(1/2x – 5) – (7/8x – 20) = (1/(2x – 5)) – (7/4(2x –5)) = (8x – 20 – 7(2x – 5))/(4(2x – 5)(2x – 5)
= (8x – 20 – 14x + 35)/4(2x – 5)² = (15 – 22x)/4(2x – 5)²
The denominator is: x/2x – 5
So we now have:
(15 – 22x)/4(2x – 5)² ÷ x/(2x – 5) = (15 – 22x)/4(2x – 5)² x (2x – 5) /X = (15 – 22x)/4x(2x – 5)
Well we set up the equation for a direct variation
<span>y=kx</span>
Lets take a point... (-8, -6)
Plug that in
<span>−6=k(−8)</span><span>
And solve for 'k' to get *indeed* 3/4</span>
Answer:
-5°C < 5°C
The temperature was higher on Wednesday than on Tuesday.
Your answer is D. as x moves towards the positive integers it increases and y goes decreases then when it hits y it then increases