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Murljashka [212]
3 years ago
9

Plzzzzz help due in 5 minsss plsssss

Mathematics
1 answer:
9966 [12]3 years ago
7 0
I believe is 251.2 sorry if it’s to late
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JKLM is a rhombus. KM is 20 and JL is 48. Find the perimeter of the<br><br> rhombus.
anygoal [31]

Answer:

104 units

Step-by-step explanation:

Given

Shape: Rhombus

JL = 48

KM = 20

Required

Determine the perimeter

The given parameter are the diagonals of the rhombus.

The perimeter (from diagonals) is calculated as thus:

P = 2\sqrt{(JL)^2 + (KM)^2}

Substitute values for JL and KM

P = 2\sqrt{48^2 + 20^2}

P = 2\sqrt{2304 +400}

P = 2\sqrt{2704}

P = 2 * 52

P = 104

<em>Hence, the perimeter is 104 units</em>

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2 years ago
Which three-dimensional object can be formed by rotating a rhombus about one of its diagonals?
Ghella [55]
Shape 3 is the correct answer


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2 years ago
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hjlf

Answer:

x=15

Step-by-step explanation:

Step 1: Multiply both sides by 2.

Step 2: Simplify both sides of the equation.

6x+18=108

Step 3: Subtract 18 from both sides.

6x+18−18=108−18

6x=90

Step 4: Divide both sides by 6.

x=15

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Tami spins a spinner with seven sections. The sections are
tia_tia [17]

Answer:

B

Step-by-step explanation:

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