Given: Normal pull of gravity g = 9.8 m/s²;
g = 0.855 m/s² (at a certain distance)
Universal gravitational constant G = 6.67 x 10⁻¹¹ N.m²/Kg²
Mass of the Earth Me = 5.98 x 10²⁴ Kg
Radius r = ?
g = GMe/r²
r = √GMe/g
r = √(6.67 x 10⁻¹¹ N.m²/Kg²)(5.98 x 10²⁴ Kg)/(0.855 m/s²)
r = 2.16 x 10⁷ m or
r = 21,610 Km
.
Answer:
the longest wavelength of incident sunlight that can eject an electron from the platinum is 233 nm
Explanation:
Given data
Φ = 5.32 eV
to find out
the longest wavelength
solution
we know that
hf = k(maximum) +Ф ...............1
here we consider k(maximum ) will be zero because photon wavelength max when low photon energy
so hf = 0
and hc/ λ = +Ф
so λ = hc/Ф ................2
now put value hc = 1240 ev nm and Φ = 5.32 eV
so hc = 1240 / 5.32
hc = 233 nm
the longest wavelength of incident sunlight that can eject an electron from the platinum is 233 nm
<span>The kinetic energy of gas molecules is directly proportional to the Kelvin temperature of the gas</span>
Answer:
The number of paces it would take to get to the Moon is 213,555,556 paces
Explanation:
The given length of Mr Galan's paces = 1.8 m/pace
The distance from the Earth to the Moon is, 384,400 km = 384,400,000 m
Therefore, the number of paces, "n", it would take to get to the Moon from the Earth is given as follows;
n = (The distance from the Earth to the Moon)/(The length of each Mr Galan's paces)
∴ n = 384,400,000 m/(1.8 m/pace) = 213,555,556 paces
The number of paces it would take to get to the Moon = n = 213,555,556 paces
