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xenn [34]
3 years ago
15

the angle of a triangle are given as 6x,(x-3), and (3x+7). find x then find the measures of the angles

Mathematics
1 answer:
kvv77 [185]3 years ago
8 0

Answer:

x =17.6

The three angles are

6x =  105.6

x-3  =14.6

3x+7 = 59.8

Step-by-step explanation:

The three angles of a triangle add to 180 degrees

6x + x-3 + 3x+7 = 180

Combine like terms

10x +4 = 180

Subtract 4 from each side

10x+4-4= 180-4

10x = 176

Divide each side by 10

10x/10 =176/10

x =17.6

The three angles are

6x = 6*17.6= 105.6

x-3 = 17.6-3 =14.6

and 3x+7 = 3(17.6)+7 =52.8+7 = 59.8

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julsineya [31]

Answer:

Part 1) sin(\theta)=-\frac{\sqrt{65}}{9}

Part 2) tan(\theta)=\frac{\sqrt{65}}{4}

Step-by-step explanation:

we have that

The cosine of angle theta is negative and the tangent of angle theta is positive

That means that the sine of angle theta is negative

step 1

Find sin(\theta)

we know that

sin^{2}(\theta) +cos^{2}(\theta)=1

we have

cos(\theta)=-\frac{4}{9}

substitute

sin^{2}(\theta) +(-\frac{4}{9})^{2}=1

sin^{2}(\theta) +\frac{16}{81}=1

sin^{2}(\theta)=1-\frac{16}{81}

sin^{2}(\theta)=\frac{65}{81}

square root both sides

sin(\theta)=\pm\frac{\sqrt{65}}{9}

Remember that

In this problem the sine of angle theta is negative

so

sin(\theta)=-\frac{\sqrt{65}}{9}

step 2

Find tan(\theta)

we know that

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

we have

sin(\theta)=-\frac{\sqrt{65}}{9}

cos(\theta)=-\frac{4}{9}

substitute the given values

tan(\theta)=-\frac{\sqrt{65}}{9}:-\frac{4}{9}=\frac{\sqrt{65}}{4}

3 0
3 years ago
at a local soccer game, 6/7 of the people were fans. one-half of those fans were wearing hats. what fraction of the people was w
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Answer: \frac{3}{7}

You simply need to multiply \frac{6}{7}*\frac{1}{2}.
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3 years ago
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sukhopar [10]
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3 years ago
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Stells [14]

Answer:

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3 years ago
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