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xenn [34]
3 years ago
15

the angle of a triangle are given as 6x,(x-3), and (3x+7). find x then find the measures of the angles

Mathematics
1 answer:
kvv77 [185]3 years ago
8 0

Answer:

x =17.6

The three angles are

6x =  105.6

x-3  =14.6

3x+7 = 59.8

Step-by-step explanation:

The three angles of a triangle add to 180 degrees

6x + x-3 + 3x+7 = 180

Combine like terms

10x +4 = 180

Subtract 4 from each side

10x+4-4= 180-4

10x = 176

Divide each side by 10

10x/10 =176/10

x =17.6

The three angles are

6x = 6*17.6= 105.6

x-3 = 17.6-3 =14.6

and 3x+7 = 3(17.6)+7 =52.8+7 = 59.8

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3 years ago
Fill in the missing portions of the function to rewrite g(x) = 3a^2 − 42a + 135 to reveal the zeros of the function. What are th
mariarad [96]

Answer:

g(x) = 3(x-9)(x-5)

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Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

g(x) = 3x^{2} - 42a + 135

So

a = 3, b = -42, c = 135

\bigtriangleup = (-42)^{2} - 4*3*135 = 144

x_{1} = \frac{-(-42) + \sqrt{144}}{2*3} = 9

x_{2} = \frac{-(42) - \sqrt{144}}{2*3} = 5

So

g(x) = 3(x-9)(x-5)

Zeros: x = 9 and x = 5.

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3 years ago
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Answer:

<h2>B) x = 2/3</h2>

Step-by-step explanation:

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