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WARRIOR [948]
3 years ago
13

(08.06 MC) Carly and Janiya put some money into their money boxes every week. The amounts of money (y), in dollars, in their mon

ey boxes after certain amounts of time (x), in weeks, are shown by the equations below: Carly y = 60x + 40 Janiya y = 50x + 80 After how many weeks will Carly and Janiya have the same amount of money in their money boxes and what will that amount be? (1 point) 5 weeks, $280 5 weeks, $340 4 weeks, $280 4 weeks, $340
Mathematics
1 answer:
Pavel [41]3 years ago
5 0
For this case we have the following equations:
 y = 60x + 40
 y = 50x + 80
 Equaling both equations we have:
 60x + 40 = 50x + 80
 From here, we clear the value of x:
 60x - 50x = 80 - 40
 10x = 40
 x = 40/10
 x = 4 weeks
 Substituting x = 4 in any of the equations we have:
 y = 60 (4) + 40
 y = 240 + 40
 y = 280 $
 Answer:
 
$ 280 4 weeks
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Answer:

There are 220 choices

Step-by-step explanation:

Given

People = 12

Selection =3 (President, Treasurer and Secretary)

Required

Determine number of selection (if no restriction)

This is calculated using the following combination formula:

^nC_r = \frac{n!}{(n - r)!r!}

Where

n = 12

r= 3

So, we have:

^nC_r = \frac{n!}{(n - r)!r!}

^{12}C_3 = \frac{12!}{(12 - 3)!3!}

^{12}C_3 = \frac{12!}{9!3!}

^{12}C_3 = \frac{12*11*10*9!}{9!3!}

^{12}C_3 = \frac{12*11*10}{3!}

^{12}C_3 = \frac{12*11*10}{3*2*1}

^{12}C_3 = \frac{12*11*10}{6}

^{12}C_3 = 2*11*10

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<em>There are 220 choices</em>

8 0
2 years ago
Mason has a collection of .49 stamps, .20 stamps and .3 stamps worth 23.55. He has 56 total .49 and .20 stamps and the number of
Nezavi [6.7K]

Answer: Mason has 40 forty-nine cent stamps, 16 twenty cent stamps and 25 three cent stamps

Step-by-step explanation:

Let x represent the number of 49 cent stamps that Mason has.

Let y represent the number of 20 cent stamps that Mason has.

Let z represent the number of 3 cent stamps that Mason has.

Mason has a collection of 49 cent stamps, 20 cent stamps, and 3 cent stamps worth $23.55. This means that

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He had 56 total 49 cent and 20 cent stamps. This means that

x + y = 56

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The number of 3 cent stamps is nine more than the number of 20 cent stamps. This means that

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Substituting x = 56 - y and z = y + 9 into equation 1, it becomes

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y = - 4.16/ - 0.26y

y = 16

x = 56 - y = 56 - 16

x = 40

z = y + 9 = 16 + 9

z = 25

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9x-6 is -63

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